Solutions
Concept:
The load-carrying capacity for a short column loaded axially with minimum eccentricity is given as
Pu = 0.4 fck Ac + 0.67 fy Asc
Where,
Ac = Area of concrete after reducing steel area, Asc = Area of steel
Calculation:
fck = 25, fy = 415, b = 300 mm, d = 450 mm
∴ Load carrying capacity,
P = 0.4 × 25 (Total area – Area of steel) + 0.67 × 415 × Asc
= 1673.37 kN
Important Point:
If, or both are less than 12 and
< 0.05 D
& < 0.05 b
The column is designed as a short axially loaded column with minimum eccentricity.
For purely axial load, i.e. eccentricity = 0
P = 0.45 fck Ac + 0.75 fy Asc