Please wait...

Newton's Laws Of Motion Test - 4
Result
Newton's Laws Of Motion Test - 4
  • /

    Score
  • -

    Rank
Time Taken: -
  • Question 1/8
    1 / -0

    A block of mass M is pulled along a horizontal friction surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is

    Solutions

    Force on block = mass × acceleration =  
    Hence, option D is correct.

  • Question 2/8
    1 / -0

    The block of mass M moving on the functionless horizontal surface collides with a spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is 

    Solutions

    Hence, option A is correct.

  • Question 3/8
    1 / -0

    A body of mass m is accelerated uniformly from rest to speed v in total time T. The Instantaneous power delivered to the body as a function of time(t) is given by

    Solutions

    P = (ma). v 
    = ma2 t 

    Hence, option A is correct.

  • Question 4/8
    1 / -0

    A boy sitting on the topmost berth in the compartment of a train which is just going to stop on a railway station drops an apple aiming at the open hand of his brother situated vertically below his hands at a distance of about 2m. The apple will fall (Neglect air resistance)

    Solutions

    According to Newton's Law of Motion, the apple will experience the same force as the boys sitting in the train (except for the free fall under gravity in the vertical direction.). Hence, the apple will fall directly in the hands of the boy.

  • Question 5/8
    1 / -0

    A machine gun fires a bullet of mass 40 g with a velocity 1200 ms−1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?

    Solutions

    Change in momentum for each bullet fired is 

    If a bullet fired exerts a force of 48 N on man’s hand so ρ man can exert maximum force of 144 N, number of bullets that can be fired = 144/48 = 3 bullets.

  • Question 6/8
    1 / -0

    A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to

    Solutions

    FavΔt = Δp 
    Fav = (0.15*20 - 0.15*0)/0.1 = 3/0.1 = 30 N

  • Question 7/8
    1 / -0

    A chain of mass M and length L held vertical by fixing its upper end to a rigid support. The tension in the chain at a distance y from the rigid support is –

    Solutions

    Tension at point P is due to lower part 

  • Question 8/8
    1 / -0

    An empty plastic box of mass m is found to accelerate up at the rate of g/6 when placed deep inside water. How much sand should be put inside the box so that it may accelerate down at the rate of g/6?

    Solutions

    Now after placing sand of mass M 
    (m + M) g – m'g = (m + M) a Here a = g/6 

User Profile
-

Correct (-)

Wrong (-)

Skipped (-)


  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Click on Allow to receive notifications
×
Open Now