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Chemistry Test - 20
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Chemistry Test - 20
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  • Question 1/10
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    The elements A, B and C belong to group 2, 14 and 16 respectively, of the periodic table. Which of the two elements will form covalent bonds?

    Solutions

    The covalent bond is formed by the sharing of electrons between two atoms. As the element B (which belongs to group 14) has 4 valence electrons which it can share with two elements of C type (from group 16) electrons to complete the octet of each included atom.

  • Question 2/10
    1 / -0

    Arrange the alkyl in decreasing order of their mass.

    Solutions

    For CH3Br:

    Atomic mass:

    =(12×1)+(1×3)+(80×1)

    =95

    For CH3Cl:

    Atomic mass:

    =(12×1)+(1×3)+(35.5×1)

    =50.5

    For H2O:

    Atomic mass:

    =(16×1)+(2×1)

    =18

    According to above data regarding atomic masses of compounds, the decreasing order will be:

    CH3Br>CH3Cl> H2O

  • Question 3/10
    1 / -0

    A commercially sold conc. HCl is 35%HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is:

    (Atomic mass: Cl=35.5amu.H=1amu )

    Solutions

    35%HCl by mass means in 100gmHCl solution 35gmHCl present.

    Now, volume of 100gmHCl solution

    =1001.46ml

    =1001.461000I

     Moles of HCl=3536.5 moles of solute 

     Now, molarity =3536.5 volume of solution ( in L)

    =3536.51001.46=14

  • Question 4/10
    1 / -0

    Which of the following has a regular repeated molecular pattern in three dimensional space?

    Solutions

    Solids have a regular repeated molecular pattern in three dimensional space and this is due to their property of high inter-molecular forces. But in liquids and gases, the arrangement of molecular pattern is irregular.

  • Question 5/10
    1 / -0

    ___________ is a quantity that represents the total energy of the system.

    Solutions

    Internal energyis a quantity that represents the total energy of the system.

  • Question 6/10
    1 / -0

    The cathode ray experiment was done for the first time by:

    Solutions

    In 1897, great physician J.J. Thompson, conducted his first cathode ray tube experiment.

    Thompson, conducted this experiment to prove that rays emitted from an electron gun are inseparable from the latent charge. He built his cathode ray tube with a metal cylinder on the other end. The metal had two small diversions(slits), leading to electrometer that could measure small electric charge.

  • Question 7/10
    1 / -0

    Which of the following cannot be a ligand?

    Solutions

    Ni2+cannot be a ligand.

    The ions/molecules bound to the central atom/ion is called a ligand. Ni2+ is a metal ion, and according to Werner, the secondary valences can be satisfied only by neutral molecules or negative ions. Cl,H2O and NH3 are all possible ligands.

  • Question 8/10
    1 / -0

    Glycerol is:

    Solutions

    Glycerol is Trihydric alcohol.

    Compounds having one −OH group is called monohydric alcohol.

    Compounds having two −OH group is called dihydric alcohol.

    Compounds having three −OH group is called trihydric alcohol.

    Image of glycerol is given below, it has three −OH group

  • Question 9/10
    1 / -0

    Electronic configuration of a transition element X in +3 oxidation state is [Ar]3d5. What is its atomic number?

    Solutions

    In oxidation, an element looses its electrons.

    There is +3 oxidation state means no. of loss of electrons is 3, and that 2 electrons are released from 4s2 orbital and 1 electron from 3d orbital to attain half filled stability.

    Therefore, [Ar] has 18 electrons and 5 electrons in 3d orbital as per given.

    Therefore, actual configuration will be [Ar]183d64s2. Therefore, atomic number will be 18+6+2=26.

    This is Fe having atomic number 26.

  • Question 10/10
    1 / -0

    If the solubility of Ag2CrO4 is s moles/litre, its solubility product will be ___________.
    Solutions
    Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as Ksp.
    The equation for the ionization of the silver chromate is given as:
    Ag2CrO42Ag++CrO42
    We are given:
    Solubility of Ag2CrO4=s mol/L
    By stoichiometry of the reaction:
    1 mole of Ag2CrO4 gives 2 moles of Ag+ and 1 mole of CrO42
    When the solubility of Ag2CrO4 is s moles/liter, then the solubility of Ag+ will be 2 s moles/liter and solubility of CrO42 will be s moles/liter.
    Expression for the equilibrium constant of Ag2CrO4 will be:
    Ksp=[Ag+]2[CrO42]Ksp=[2s]2[s]=4s3
    Thus, the solubility product of Ag2CrO4 is 4s3.
     
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