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JEE Advanced Mix Test 39
Result
JEE Advanced Mix Test 39
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Time Taken: -
  • Question 1/10
    4 / -1

    Solutions

  • Question 2/10
    4 / -1

    Let f : R → R and g : R → R be two one - one and onto functions such that they are mirror images of each other about the line y = 0, then h (x) = f(x) + g(x) is

    Solutions

    f : R → R & g : R →R be two one-one onto functions such that f & g are mirror images of each other about line y = 0. It means one is –ve of the other

    i.e. f(x) = – g(x)

    ⇒ f(x) + g(x) = 0

    ⇒ h(x) = 0

    h(x) is not onto as well as not one-one

  • Question 3/10
    4 / -1

    The function f (x) = (x2 – 1) |x2 – 3x + 2| + cos |x| is not differentiable at x =

    Solutions

  • Question 4/10
    4 / -1

    The function f (x) = (x – [x]) sin p x is, (where [.] denotes greatest integer function)

    Solutions

  • Question 5/10
    4 / -1

    If f(x) = x3 + ax2 + ax + x(tanθ + cotθ) is increasing for all real x and if  then

    Solutions

  • Question 6/10
    4 / -1

    For what values of a, m and b, Lagrange's mean value theorem is applicable to the function f(x) for x [0, 2]

    Solutions

  • Question 7/10
    4 / -1

     does not have critical points if 'a' equal to

    Solutions

  • Question 8/10
    4 / -1

    Solutions

  • Question 9/10
    4 / -1

    Solutions

  • Question 10/10
    4 / -1

    Which of the following is/are true

    Solutions

    If f is continuous at a point. Then |f| will also continuous at that point.

    If f is differentiable then f|f| will also be differentiable

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