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Chemical Kinetics Test - 11
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Chemical Kinetics Test - 11
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  • Question 1/10
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    Naturally occurring potassium consists of 0.01% at 40 K which has a half-life of 1.28 x 109 yr. Activity of 1.00 g sample of KCl is

     

    Solutions

     

     


    Number of 40 K atoms in 1g KCI


     

     

  • Question 2/10
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    Direction : This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).

    Passage l

    Isotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14 O and 15 O, Also t50 (14 O) = 71s, t50 (15 O) = 124s.

    Q. Ratio of rate constants of 14 O to 15 O  is

     

    Solutions

     

     





     

     

  • Question 3/10
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    Passage l

    Isotope of oxygen with mass number less than 16 undergoes β+ -emission. Assume an equimolar mixture of 14 O and 15 O, Also t50 (14 O) = 71s, t50 (15 O) = 124s.

    Q. Ratio of 14 O to 15 O  left after 1.00 h is

     

    Solutions

     

     





     

     

  • Question 4/10
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    Passage II

    Consider acid-hydrolysis of ester which is first order reaction.

    CH3 COOC2 H5 + H2 O  CH3 COOH + C2 H5 OH

    Kinetics is studied by titration of the acid with NaOH at a given time.
    V0 = Volume of NaOH at start, Vt = Volume of NaOH at time t, V = Volume of NaOH at the end of the complete hydrolysis.

    Q. 
    Rate constant k is given by

     

    Solutions

     

     



    At time t  = 0, volume of NaOH is due to H+ (catalyst) = V0 and remains constant
    at time t, volume of NaOH is due to H+ and CH3 COOH = Vt


    At infinite time (complete reaction), volume of NaOH is due to total CH3 COOH (or ester) and H+ = a + V0





    If ester is 50% hydrolysed, 



     

     

  • Question 5/10
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    Passage II

    Consider acid-hydrolysis of ester which is first order reaction.

    CH3 COOC2 H5 + H2 O  CH3 COOH + C2 H5 OH

    Kinetics is studied by titration of the acid with NaOH at a given time.
    V0 = Volume of NaOH at start, Vt = Volume of NaOH at time t, V = Volume of NaOH at the end of the complete hydrolysis.

    Q.

    If ester is 50% hydrolysed, then  

     

    Solutions

     

     



    At time t  = 0, volume of NaOH is due to H+ (catalyst) = V0 and remains constant
    at time t, volume of NaOH is due to H+ and CH3 COOH = Vt


    At infinite time (complete reaction), volume of NaOH is due to total CH3 COOH (or ester) and H+ = a + V0





    If ester is 50% hydrolysed, 



     

     

  • Question 6/10
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    Passage III

    I, II and III are three vessels of equal volumes containing molecules of A as shown and in each A decomposes into products.

    Q. 
    Initial rate of decomposition of A will be in order in these three vessels as

     

    Solutions

     

     


    Thus, ratio fo rates = 6 : 1 2 : 9 = 1 : 2 : 1 5
    For first order reaction T50  is independent of initial concentration.
    Thus, T50 will be equal to 1 :1 :1.

     

     

  • Question 7/10
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    Passage III

    I, II and III are three vessels of equal volumes containing molecules of A as shown and in each A decomposes into products.

    Q. 
    Time of 50% decomposition is in order

     

    Solutions

     

     


    Thus, ratio fo rates = 6 : 1 2 : 9 = 1 : 2 : 1 5
    For first order reaction T50  is independent of initial concentration.
    Thus, T50 will be equal to 1 :1 :1.

     

     

  • Question 8/10
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    Direction : This section contains 3 questions. When worked out will result in one integer from 0 to 9 (both inclusive).This section contains 3  questions, when worked out will result in an integer value from 0 to 9 (both inclusive)

    Q. A radioactive element gets spilled over the floor of a room. Its half-life period is 30 days. If the initial activity is ten times the permissible value, it will be safer to enter the room after 10n days. What is the value of n?

     

    Solutions

     

     

    Permissible element = 10 times the initial value






     

     

  • Question 9/10
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    For the first order reaction, variation of log10 (a - x)vs time (t) is shown below.

    Q. 
    Its half-life period is logx. What is the value of x?

     

    Solutions

     

     





     

     

  • Question 10/10
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    For the first order reaction,

    Q. 
    If OA = 1.3010 then reactant left after 0.6021 min i s .......unit.

     

    Solutions

     

     

     At time t = 0, x = 0

     

     

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