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Mathematics Test 215
Result
Mathematics Test 215

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  • Question 1/10
    4 / -1

    If A = {θ : 2cos2θ + sin θ ≤ 2} and  then A ∩ B is equal to

    Solutions


     

  • Question 2/10
    4 / -1

    Let a relation R be defined by R = {(4, 5), (1, 4), (4, 6), (7, 6), (3, 7)}. The relation R-1oR is given by

    Solutions

     

  • Question 3/10
    4 / -1

    Solutions


     

  • Question 4/10
    4 / -1

    The function 

    Solutions

     

  • Question 5/10
    4 / -1

    If f(a + b - x) = f(x), then  is equal to

    Solutions

     

  • Question 6/10
    4 / -1

    For all the real values of x, if f(x) + f(x + 8) = f(x + 4) + f(x + 12), g(x)  f(x) dx and g(1) = 2, then the value of g(12) is

    Solutions

    f(x) + f(x + 8) = f(x + 4) + f(x + 12)

    Replacing x by x + 4, we get

    f(x + 4) + f(x + 12) = f(x + 8) + f(x + 16)

    Subtracting one from the other, we get

    f(x) = f(x + 16)

    g'(x) = f(x + 16) - f(x)

    g'(x) = 0

    g(x) = k

    g(1) = 2

    ∴ k = 2

    ∴ g(12) = 2

     

  • Question 7/10
    4 / -1

    If the lines represented by the equation 3y2 - x2 + 2- √3x - 3 = 0 are rotated about the point (√3, 0) through an angle 15°, one in clockwise direction and other in anticlockwise direction, so that they become perpendicular, then the equation of the pair of lines in the new position is

    Solutions

    The given equation of the pair of straight lines can be rewritten as

     

  • Question 8/10
    4 / -1

    If  then the value of  is

    Solutions

     

  • Question 9/10
    4 / -1

    A box contains 100 tickets numbered 1 to 100. If 2 tickets are drawn successively without replacement from the box, what is the probability that all the tickets bear numbers divisible by 10?

    Solutions

    No. of tickets numbered from 1 to 100, divisible by 10 = 10

    Let,

    Event (A) = Drawing 2 tickets successively without replacement which are divisible by 10.

     

  • Question 10/10
    4 / -1

    Solutions

     

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