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Mass spectroscopy is done for a sample-
Mass spectrometry is a procedure wherein a compound is bombarded with electrons to generate ions.
These ions are then sorted out by accelerating them through an electric and magnetic field.
It is then separated according to their specific mass-to-charge ratio where the radius of the trajectory is proportional to the mass of a charged particle moving in uniform electric and magnetic field.
The sample has to be in a gaseous state in order to be ionized.
Hence, the sample has to be converted into a gaseous state before the procedure begins.
A meter is divided into 100 parts. Each part is equal to ________
Some universal standards about the length and other physical quantities have been decided by an international organization.
These standards are universally accepted for measurements and scientific purposes.
These units are called "International system of units" or SI units.
Length is the SI unit of measurement of distance.
Now, it is convenient to measure the distances in meters up to some extent. To measure the other distances, units that are multiples or divisions of meters are used.
The centimeter is used to measure certain small distances.
A centimeter is 100th part of meter or we can say that
What is the dimensional formula of strain?
Strain:
The ratio of change in configuration to the original configuration is called strain.
Strain = Change in dimension / Original dimension
As the strain is the ratio of two like quantities, it has no units and no dimensions.
and has no dimension.
Its dimension can be expressed as M0L0T0.
The correct answer is M0L0T0.
A boy starts at position A, travels 3 kilometres to point B, and then returns to point A. If it takes two hours for this, his speed is
To find the speed of the boy, we can use the formula:
Speed = Distance / Time
In this case, the total distance traveled is 3 kilometers to point B and 3 kilometers back to point A,
so the total distance is 3 + 3 = 6 kilometers.
The total time taken is given as 2 hours.
Speed = 6 km / 2 hours=3 km/h
So, the correct answer is (a) 3 km/h.
A body starts off at rest and moves in a straight line with a constant acceleration. If its velocity is 8 m/s with a displacement of 32 m, its acceleration is
We can use the following kinematic equation to relate initial velocity (u), final velocity (v), acceleration (a), and displacement (s):
v2 = u2 + 2as
In this scenario, the body starts at rest, so the initial velocity u is 0 m/s. The final velocity v is given as 8 m/s, and the displacement s is 32 m. We want to find the acceleration a.
82 = 02+ 2a(32)
64 = 64a a = 1 m/s2
So, the correct answer is (a) 1 m/s².
A body begins at rest and moves for t seconds at 2 m/s2 uniform acceleration. If it causes a displacement of 16 m, the time of t is
Option a is the correct answer as because when we put the values as S = 16, a = 2 and u = 0 in the equation S = ut + 1/2 at2
A body starts from rest. If the body travels with an acceleration of 2 m/s², its displacement after 3 seconds is
We can use the kinematic equation to find the displacement (s):
s = ut +1/2at2
In this case, the body starts from rest (u = 0m/s), and the acceleration (a) is given as 2m/s2. The time (t) is 3 seconds.
s = 0⋅3 + 1/2(2)(3)2
s= 0 + 1/2(2)(9)
s = 9m
So, the correct answer is (a) 9 m.
A body begins from rest and travels with an acceleration of 2 m/s2 . After t seconds the velocity of the body is 10 m/s. Then time, t is
We can use the kinematic equation to relate initial velocity (u), acceleration (a), time (t), and final velocity (v):
v = u + at
In this case, the body begins from rest, so the initial velocity u is 0 m/s. The acceleration a is given as 2m/s2, and the final velocity v is 10 m/s. We want to find the time t.
10 = 0 + (2)t
t = 2 / 10
t = 5s
So, the correct answer is (b) 5 s.
A body begins at rest and accelerates uniformly to cover a distance of 6 metres. If its velocity after the displacement is 6 m/s, then its uniform acceleration a is
We can use the kinematic equation to relate initial velocity (u), acceleration (a), distance (s), and final velocity (v):
In this case, the body begins at rest, so the initial velocity u is 0 m/s. The final velocity v is given as 6 m/s, and the distance s is 6 m. We want to find the acceleration a.
62 = 02 + 2a(6)
36 = 12a
a = 36/12
a = 3m/s2
So, the correct answer is (c) 3 m/s².
A man throws balls vertically upwards at the same speed, one after the other, with a 2 second interval. What should the throw speed be if more than two balls are in the air at the same time?
The key factor to consider is that the balls are thrown vertically upwards, and they experience free fall under gravity. The time of flight for a vertically thrown object can be determined by the equation:
where: t is the time of flight, u is the initial velocity, g is the acceleration due to gravity (approximately 9.8m/s2).
If the balls are thrown with a 2-second interval, we need to ensure that the first ball has enough time to reach its maximum height and start descending before the second ball is thrown. This means that the time of flight for each ball should be more than 2 seconds.
Let's use the equation to find the minimum initial velocity u that satisfies this condition:
So, the throw speed should be more than 4.9 m/s to ensure that more than two balls are in the air at the same time.
Therefore, the correct answer is (b) More than 19.6 m/s.
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