Solutions
Explanation : A = {(a, a2, a3-1) (b, b2, b3-1) (c, c2, c3-1)}
=> {(a, a2, a3) (b, b2, b3) (c, c2, c3)} - {(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0
=> abc{(1, a, a2) (1, b, b2) (1, c, c2)} - {(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0
=> abc{(a, a2, 1) (b, b2, 1) (c, c2, 1)} - {(a, a2, 1) (b, b2 1) (c, c2, 1)} = 0
=> (abc-1){(a, a2, 1) (b, b2, 1) (c, c2, 1)} = 0
abc - 1 = 0
=> abc = 1