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JEE Main Test 138
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JEE Main Test 138
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  • Question 1/10
    4 / -1

    Ten moles of an ideal gas at constant temperature 500 K is compressed from 50 L to 5 L. Work done in the process is (Given, R = 8.31 J – mol -1 – K -1)

  • Question 2/10
    4 / -1

    A Carnot engine, having an efficiency of η = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

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  • Question 3/10
    4 / -1

    A motor is rotating at a constant angular velocity of 600 rpm. The angular displacement per second is

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  • Question 4/10
    4 / -1

    For the given uniform square lamina ABCD, whose centre is O

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  • Question 5/10
    4 / -1

    The species having bond order different from that in CO is

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  • Question 6/10
    4 / -1

    If P, Q and R are angles of ΔPQR, then the value of

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  • Question 7/10
    4 / -1

    The shape of XeO2 F2 molecule is

    Solutions

    The shape of XeO2F2 molecule is see-law shape. Bacause, after drawing the Lewis structure and determining the best one based on formal charges, the xenon atom is left with one lone pair, two double bonds to the oxygen atoms and two single bonds to the fluorine atoms. This is a total of 5 electron domains and 4 different atoms, consist with AX4E formula of the see-saw molecular geometry.

     

  • Question 8/10
    4 / -1

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  • Question 9/10
    4 / -1

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  • Question 10/10
    4 / -1

    Solutions

     

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