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Profit, Loss And Discount Test - 1
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Profit, Loss And Discount Test - 1

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  • Question 1/10
    3 / -1

    A man sells a TV set for Rs. 33000 and makes a profit of 10%. He sells another TV at a loss of 20%. If on the whole, he neither gains nor loses, find the selling price of the second TV set.

    Solutions

    Here, the selling price = 33000

    profit made = 10%

    therefore original price =»x+10% of x = 33000

    x = 33000 - 10% of x

    x = 33000- 1/10 of x

    10x = 330000-1x

    11x = 330000

    x = 330000/

    = 30000

    therefore profit = 33000-30000 = 3000

     

    here, he sells another tv for a loss of 20%

    which is selling price - 20%of original price

    = 33000 - 20% of 30000

    = 30000- ( 20 × 30000)

    100

    = 33000 - 6000 = 27000

    So option C is correct

  • Question 2/10
    3 / -1

    A feeding bottle is sold for Rs. 150. Sales tax accounts for one-fifth of this and profit one-third of the remainder. Find the cost price of the feeding bottle. 

    Solutions

    Sales tax = 150 / 5 = 30
    ∵ SP contains Rs. 30 component of sales tax.
    Of the remainder (150 – 30 = 120) 1/3rd is the profit.
    Thus, the profit = 120 / 3 = 40
    Hence, Cost price = 120 – 40 = 80

    So option B is correct

  • Question 3/10
    3 / -1

    By selling a cap for Rs. 29.75, a man gains 6.25%. What will be the CP of the cap? 

    Solutions

    SP = 106.25% of the CP.
    Thus, CP = 29.75/1.0625 = Rs. 28

    So option D is correct

  • Question 4/10
    3 / -1

    E sells a car priced at Rs. 1,80,000. He gives a discount of 5% on the first Rs. 1,00,000 and 12.5% on the remaining Rs. 80,000. His competitor R sells a car on the same market priced at Rs. 1,80,000. If he wants to be competitive what percent discount should R offer on the marked price.

    Solutions

    The total discount offered by E = 5% on 1,00,000 + 12.5% on 80,000 = 5,000 + 10,000 = 15,000.

    If R wants to be as competitive, he should also offer a discount of Rs. 15,000 on 1,80,000.

    Discount percentage = (15000/180000) x 100= 8.33% discount.

    So option B is correct

  • Question 5/10
    3 / -1

    E owns a house worth Rs. 20,000. He sells it to R at a profit of 25%. After some time, R sells it back to E at 25% loss. Find E’s loss or gain per cent.

    Solutions

    CP = 20000
    Profit = 25/100 of 20000 = 5000
    SP = Profit + CP = 25000

    New transaction

    CP= 25000
    Loss = 25% of 25000 = 6250
    SP = CP - Loss = 18750

    P's gain = 1250
    TOTAL gain = 6250
    Total gain % = 6250/20000 × 100 = 625/20 = 31.25%

    So option C is correct

  • Question 6/10
    3 / -1

    A machine costs Rs. 1025. If it is sold at a loss of 25%, what will be its cost price as a percentage of its selling price? 

    Solutions

    A loss of 25% means a cost price of 100 corresponding to a selling price of 75. CP as a percentage of the SP would then be 133.33%

    Alternatively,

    Cost price = 1025
    Loss% = 25%
    SP = 1025 - (1025 * 25/100) = 768.75
    ⇒ 768.75 * (x/100) = 1025
    ⇒ 768.75x = 102500
    ⇒ x = 102500/768.75 = 133.33%

    So option D is correct

  • Question 7/10
    3 / -1

    A man sells an article at 10% above its cost price. If he had bought it at 15% less than what he paid for it and sold it for Rs. 33 less, he would have gained 10%. Find the cost price of the article.

    Solutions

    S.P. at 10% profit = Rs.(110y/100) = 11y/10
    New C.P. of article = 85y/100 = 17y/20
    S.P. = Rs.(17y/20 * 110/100)
    New S.P. of article = Rs. 187/200

    According to Question,
    11y/10 - 187y/200 = 33
    33y/200 = 33
    y = 200

    So option B is correct

  • Question 8/10
    3 / -1

    A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the cus- tomer. Besides, he also cheats both his supplier and his buyer by 100 grams while buying or selling 1 kilogram. Find the percentage profit earned by the shopkeeper.

    Solutions

    While buying, he buys 1100 grams instead of 1000 grams (due to his cheating).
    Suppose he bought 1100 grams for Rs. 1000
    While selling, he sells only 900 grams when he takes the money for 1 kg.

    According to the problems
    He sells at 8% profit (20% markup and 10% discount).
    Hence his selling price is Rs. 1080 for 900 grams.

    To calculate profit percentage, we either equate the goods or the money.
    In this case, let us equate the money as follows:
    Buying:1100 grams for Rs. 1000
    Hence 1188 grams for Rs. 1080
    Selling: 900 grams for Rs. 1080
    Hence, profit% = 288/900 = 32%
    (using goods left by goods sold formula) 

    So option D is correct

  • Question 9/10
    3 / -1

    E sold at table to R at a profit of 25%.R sold the same table to S for Rs. 90 thereby making a profit of 20%. Find the price at which E bought the table from Z if it is known that Z gained 25% in the transaction.

    Solutions

    R sold the table at 20% profit at Rs. 90. Thus R's cost price x 1.2 = 90
    R’s Cost price = Rs. 75

    We also know that E sold it to R at 25% profit.
    Thus, E’s Cost price x 1.25 = 75
    ⇒ E’s cost price = 60

    So option D is correct

  • Question 10/10
    3 / -1

    125 toffees cost Rs. 75. Find the cost of one million toffees if there is a discount of 40% on the selling price for this quantity.

    Solutions

    The cost per toffee = 75 / 125 = Rs. 0.6 = 60 paise.
    Cost of 1 million toffees = 600000.
    ∵ There is a discount of 40% offered on this quantity.
    Thus, the total cost for 1 million toffees is 60% of 600000 = 360000 

    So option C is correct

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