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Hydrocarbons Test - 22
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Hydrocarbons Test - 22

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  • Question 1/7
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    Direction (Q, Nos. 1 - 5) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

    Q. Which molecule will give the following dicarboxylic acid upon treatment with acidic solution of KMnO4?

    Solutions

    The correct answer is Option D.
     

  • Question 2/7
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    Propose major product of the following reaction.

  • Question 3/7
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    An  optically active alky bromide X (C6H13Br) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula (C6H12). Y and Z are positional isomers. Z upon treatment with cold, dilute alkaline KMnO4 solution gives a meso-diol. Hence, X is

  • Question 4/7
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    Which starting material should be used to produce the compound shown below?

    Solutions

    The correct answer is option B

  • Question 5/7
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    When reacted with an alkene, which of the following reagent would not introduce I atleast one hydroxyl (— OH) group into final product?

  • Question 6/7
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    Direction (Q. Nos. 6 and 7) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

    Statement I :  In reductive ozonolysis, dimethylsulphide is better reducing reagent than Zn- H2O.
    Statement II : (CH3)2S brings about homogeneous catalysis.

  • Question 7/7
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    Statement I :  cis-2-butene with cold, dilute, alkaline KMnO4 gives meso-2,3- butanediol.
    Statement II :  In alkaline solution, under cold condition, KMnO4 acts as a mild oxidising agent.

    Solutions

    The correct answer is B.

    Statement I:
    cis-2-Butene on reaction with cold dilute KMnO4,
    the solution produces meso2,3butanediol.
    It is a dihydroxylation reaction and two -OH groups are added across the C=C bond.

    Statement II:
    2KMnO4 + H2O + KI → 2MnO2 + 2KOH + KIO3
    ​
    I + 6OH−→ IO3− + 3H2O + 6e−
    When alkaline KMnO4 is treated with KI, I−
    is oxidised to IO3−
    But, Statement II is not the correct explanation of Statement I.

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