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Chemistry Test 145
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Chemistry Test 145

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  • Question 1/10
    4 / -1

    Copper reduces  into NO and NO2 depending upon concentration of HNO3 in solution. Assuming  [Cu2+] = 0.1M, and PNO = PNO2 = 10–3 bar. At which concentration of HNO3, thermodynamic tendency for reduction of  into NO and NO2 by copper is same?

    Solutions

     

  • Question 2/10
    4 / -1

    A radioactive material (t1/2 = 30 days) gets spilled over the floor of a room. If initial activity is ten times the permissible value, after how many days will it be safe to enter the room

    Solutions

    It will be safe to enter the room after the nuclei decreases to 1/10 of its initial amount.

    → Half life = 30 days

    ∴ After 100 days, it will be safe to enter the room.

     

  • Question 3/10
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    Solutions

    Trinitro benzene diagenium ionis strong electrophile type and show coupling even with mesitylene

     

  • Question 4/10
    4 / -1

     A mixture of all possible stereoisomers from the above structure is subjected to fractional distillation, which of the following statements is correct

  • Question 5/10
    4 / -1

    Which of the following about SF4, SOF4 and COF2 molecules is correct?

    Solutions

    Equatorial FSF bond angle is less in SF4 than in SOF4 since lone pair repulsion is more than two electron pairs in double bond

    In both SF4 and SOF4 the hybridisation state of S is same sp3d

    The OCF bond angle on COF2 is more than 120° since two electron pairs in double bond repel more than one electron pair in C-F bonds.

    Due to repulsion by lone pair the axial FSF bond angle is less than 180°

     

  • Question 6/10
    4 / -1

    B2O3 substitutes nonmetal oxides from several metal salts because

    Solutions

    Less volatile with more melting point (B2O3) acidic oxide can substitute more volatile acidic oxides.

     

  • Question 7/10
    4 / -1

    Which of these is most stable?

    Solutions

    NCl3, NBr3 and NI3 are explosive.

     

  • Question 8/10
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    A is

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  • Question 9/10
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    Formation of “B” through the attack of first two reagents involve respectively

    Solutions

     

  • Question 10/10
    4 / -1

    Product “C” is

    Solutions

     

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