Please wait...

Physics Test 137
Result
Physics Test 137
  • /

    Score
  • -

    Rank
Time Taken: -
  • Question 1/10
    4 / -1

    The size of the image of an object, which is at infinity, is formed by a convex lens of focal length 30 cm is 2 cm. If a concave lens of focal length 20 cm is placed between the convex lens and the image at a distance of 26 cm from the convex lens, calculate the new size of the image

    Solutions

    Image formed by convex lens at ^ will act as a virtual object for concave lens. For concave lens

    Magnification for concave lens

    As height of the image at h is 2 cm.
    Therefore, height of image at I2 will be 2 x 1.25 = 2.5 cm

     

  • Question 2/10
    4 / -1

    A network of Four capacitors of capacity equal to C1 = C, C2 = 2C, C3 = 3C and C4 = 4C, are connected to a battery as shown in the figure. The ratio of the charges on C2 and C4 is

    Solutions

    All the capacitors in upper branch are in series so the charge on each capacitor is 

    Also charge on capacitor C4 is Q = 4CV

     

  • Question 3/10
    4 / -1

    A rod AD, consisting of three segments AB, BC and CD joined together, is hanging vertically from a fixed support at A. The lengths of the segments are respectively 0.1 m, 0.2 m and 0.15 m. The cross - section of the rod is uniform 10-4 m2. A weight of 10 kg is hung from D. Calculate the displacements of point D if YAB = 2.5 x 1010 N/m2, YBC = 4 x 1010 N/m2 and YCD = 1 x 1010 N/m2. (Neglect the weight of the rod.)

    Solutions

     

  • Question 4/10
    4 / -1

    A block of mass m & charge q is released on a long smooth inclined plane. Magnetic field B is constant, uniform, horizontal and out of the plane of paper as shown. Find the time from start when block loses contact with the surface.

    Solutions

    Block will loose contact with surface when force due to magnetic field will become equal to mg cos θ

     

  • Question 5/10
    4 / -1

    A battery of internal resistance 4Ω is connected to the network of resistances as shown in figure. In order that the maximum power can be delivered to the network, the value of R in $$ should be

    Solutions

    The given circuit is a balanced Wheatstone's bridge.

    Thus, no current will flow across 6R of the side CD. The given circuit will now be equivalent to

    For maximum power, net external resistance
    = Total internal resistance
    or 2R = 4
    or R = 2Ω. 

     

  • Question 6/10
    4 / -1

    In the circuit shown in diagram, the equivalent resistance between point A and B is

    Solutions

    The circuit shown in diagram (1) can be redrawn as shown in diagram (2).

    ∴  RAB = 5R/8

     

  • Question 7/10
    4 / -1

    Two trains, which are moving along different tracks in opposite directions, are put on the same track due to a mistake. Their drivers, on noticing the mistake, start slowing down the trains when they are 300 m apart. Graphs given below show their velocities as a function of time as they slow down. The separation between the trains, when both have stopped, is:

    Solutions

    Initial distance between trains is 300 m. Displacement of 1st train is calculated by area under V-t.

    Displacement of train  Which means it moves towards left.
    ∴ Distance between the two is = 300 - 280 = 20 m

     

  • Question 8/10
    4 / -1

    A tuning fork sends out waves of wavelength 68.75 cm and 3 m in air and hydrogen gas respectively. If the velocity of sound in air is 330 ms-1, find the velocity of sound in hydrogen. Also, find the frequency of the tuning fork

    Solutions

    In air : λa = 68.75 cm = 0.6875 m ; va = 330 ms-1 Let v be the frequency of the tuning fork. Then,

     

  • Question 9/10
    4 / -1

    A particle executes S.H.M. given by x = 0 · 24 cos (400 t - 0.5) in SI units. Find amplitude

    Solutions

    Here, x = 0.24 cos (4001 - 0.5) ...(i)
    The standard equation for S.H.M. is

    Comparing the equations (i) and (ii),we have
    r = 0.24 m

     

  • Question 10/10
    4 / -1

    A lens (μ = 1.5) is coated with a thin film of refractive index 1.2 in order to reduce the reflection from its surface at λ = 4800 Å. Find the minimum thickness of the film which will minimise the intensity of the reflected light. (Assume near normal incidence)

    Solutions

     

User Profile
-

Correct (-)

Wrong (-)

Skipped (-)


  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Click on Allow to receive notifications
×
Open Now