Solutions
Scenario:
We observe that each letter is written the times as the letter’s serial number in alphabets.
The series consists of alphabets in the following manner:
A (1st in series), 2 times B (2nd, 3rd), 3 times C (4th,5th, 6th), 4 times D (7th, 8th, 9th, 10th) and so on….…
Each letter is written the times as the letter’s serial number in alphabets. Also, If the serial number of letters in alphabets is n, after writing n times the number of letters in the series follows the pattern .
Example: After writing last D which is 10th number in the series and 4th number in alphabets written 4 times, the pattern satisfies, i.e.
Analysis:
Now, the 240th number may be the end of a letter, or may be repetition of a letter at any position, but still, the following equality will hold true:
n (n + 1) ≤ 480
The maximum value of n for which this equality holds true is n = 21, i.e.
∴ The 21st number in alphabets after writing 21 times will give 231st number in the series which is U. V is 22nd number in the alphabets which is written 22 times.
But since 240 - 231 = 9, after “U”, the 9th letter in series will be “V” as “V” is written 22 times.
∴ The 240th letter is “V”.