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Molecular Basis of Inheritance Test - 1
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Molecular Basis of Inheritance Test - 1
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  • Question 1/10
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    E.coli was used as a tool for which of the following?
    a. Discovery of transformation
    b. Semi-conservative replication
    c. Discovery of transduction
    d. Discovery of DNA as transforming factor

    Solutions

    E. coli was used as a tool for the discovery of semi-conservative replication by Messelson and Stahl. E. coli, along with T2 phage, was used for discovery of transduction.

  • Question 2/10
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    If a B DNA molecule is 68 Angstrom long, then how many base pairs does it contain?

    Solutions

    If a DNA molecule is 68 Angstrom long, it would contain 20 base pairs. The distance between two bases is 3.4 Angstrom. Thus, number of base pairs in 68 Angstrom long molecule is 68/3.4 = 20 base pairs.

  • Question 3/10
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    DNA ligase is an important enzyme that takes part in DNA replication. Which of the following roles does it play?

    Solutions

    DNA ligase is a specific type of enzyme that facilitates the joining of DNA strands together by catalysing the formation of a phosphodiester bond. Ligase is involved in formation of a phosphodiester bond starting from the 3'-OH of one Okazaki fragment and the 5'-phosphate of the next on the lagging strand.

  • Question 4/10
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    What was the contribution made by Chargaff in proposition of double helical model of DNA by Watson and Crick?

    Solutions

    Chargaff discovered two rules that helped lead to the discovery of the double helix structure of DNA.
    The first rule was that in DNA, the number of guanine units is equal to the number of cytosine units, and the number of adenine units is equal to the number of thymine units.
    This hinted at the base pair makeup of DNA.
    The second rule was that the relative amounts of guanine, cytosine, adenine and thymine bases vary from one species to another. This hinted that DNA rather than protein could be the genetic material.

  • Question 5/10
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    Which of the following linkages help(s) in the formation of base pairs in DNA molecule?

    Solutions

    In DNA molecule, hydrogen bonds connect the base pairs. Adenine is bonded to thymine by two hydrogen bonds and guanine is attached to cytosine by three hydrogen bonds.

  • Question 6/10
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    Histones are proteins which are involved in the formation of nucleosomes in the cell. They are rich in

    Solutions

    Histones are rich in lysine and arginine. Lysine and arginine are basic amino acids that bind to the acidic ions present in DNA molecules to form a nucleosome.

  • Question 7/10
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    In a cell, the process of transcription takes place in

    Solutions

    In a cell, the process of transcription takes place inside the nucleus.
    Transcription is the process of copying information from one strand of DNA to RNA.

  • Question 8/10
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    Which of the following chromosomes in the human genome have the maximum and minimum number of genes, respectively?

    Solutions

    In human genome, chromosome 1 has the maximum number of genes, whereas chromosome Y has the minimum number of genes. There are 2968 genes in chromosome 1 and 231 genes in chromosome Y.

  • Question 9/10
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    In which of the following gene sequences would a mutation invariably influence the binding of RNA polymerase to DNA?

    Solutions

    Mutation in promoter would invariably influence the binding of RNA polymerase to DNA. Promoter sequence contains specific DNA sequences where RNA polymerase can bind and start transcription.

  • Question 10/10
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    A cistron is a segment of DNA coding for a polypeptide. Which of the following statements about cistron of eukaryotes is/are true?
    a. It is monocistronic.
    b. It is polycistronic.
    c. Genes in eukaryotes are split.
    d. Cistron possesses only coding sequences.

    Solutions

    Monocistronic mRNA is a mRNA that encodes only one protein and all eukaryotic mRNAs are monocistronic. Genes in eukaryotes are split and have interrupted coding sequences.

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