An X-ray tube is operated at a constant potential difference and it is required to get X-ray of wavelength not less than 0.2 nanometre. Then, the potential difference in kV is (h = 6.63 × 10^-34Js, e = 1.6 × 10^-19 C, c = 3 × 10⁸ m/s)

Ultraviolet radiation of 6.2 eV falls on an aluminium surface (work function 4.2 eV). The kinetic energy of the faster electron emitted is approximately

Which of the following graphs shown in the options represents the variation of photoelectric current (i) with intensity (I) of the incident light?

K₁ and K₂ are the respective maximum kinetic energies of the photoelectrons emitted when lights of wavelengths λ₁ and λ₂ are incident on a metallic surface. If λ₁ = 3λ_2\, then

The figure shows variation of photocurrent with anode potential for a photosensitive surface for three different radiations. Let I_a, I_b and I_c be the intensities and ν_a, ν_b and ν_c be the frequencies for the curves a, b and c, respectively. Then,

Which of the following graphs correctly represents the variation of maximum kinetic energy of photoelectrons with applied frequency (ν)?

If the wavelength of incident light changes from 400 nm to 300 nm, then the stopping potential for photoelectrons emitted from a surface becomes (approximately)

Light rays of wavelength 6000  and photon intensity 39.6 watt/m² are incident on a metal surface. If only one percent of photons incident on the surface emit photoelectrons, then what will be the number of electrons emitted per second per unit area from the surface? (Planck's constant = 6.64 10^-34 J-s, velocity of light = 3 x 10⁸ m/s)

A photon of energy 8 eV is incident on metal surface of threshold frequency 1.6 x 10¹⁵ Hz. The magnitude of kinetic energy of the photo electrons emitted (in eV) is (Take h = 6 x 10^-34 Js)

In a photoelectric effect measurement, the stopping potential for a given metal is found to be V₀ volt when a radiation of wavelength λ0 is used. If radiation of wavelength 2λ₀ is used with the same metal, then the stopping potential (in volt) will be