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JEE Main Test 48
Result
JEE Main Test 48

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  • Question 1/10
    4 / -1

    Solutions

    2(8 + 3λ) + (4 + λ2) + 2(3 - 2λ) = 0

    λ2 + 2λ + 26 = 0

    D = b2 - 4ac

    D = 22 - 4 × 26 = -100

    which does not give any real value of λ.

     

  • Question 2/10
    4 / -1

    Solutions

     

  • Question 3/10
    4 / -1

    Solutions

     

  • Question 4/10
    4 / -1

    In a transformer, the number of turns in the primary coil is 140 and that in the secondary coil is 280. If current in the primary coil is 4 A, then that in the secondary coil is

    Solutions

     

  • Question 5/10
    4 / -1

    Solutions

     

  • Question 6/10
    4 / -1

    If CP and CV denote the specific heats of nitrogen per unit mass at constant pressure and constant volume, respectively, then

    Solutions

     

  • Question 7/10
    4 / -1

    The hydration energy of Mg2+ is larger than that of

    Solutions

    The cation with a higher charge density has a greater heat of hydration.

    The order is: Na+ < Mg+2 < Mg+3 < Al+3

    Because of the smaller size of Mg2+ than Na+ (both are isoelectronic with higher nuclear charge on Mg2+), the hydration energy of Mg2+ is larger than that of Na+.

     

  • Question 8/10
    4 / -1

    Directions: Identify the incorrect statement.

    Solutions

     

  • Question 9/10
    4 / -1

    Which one of the following species is not a pseudohalide?

    Solutions

    Pseudohalides are monovalent anions that have properties similar to those of halide ions.

    The corresponding dimers of pseudohalides are known as pseudohalogens. 

    RCOO- is not a pseudohalide.

     

  • Question 10/10
    4 / -1

    The correct order of EoM2+/M values with negative sign for the four successive elements Cr, Mn, Fe and Co is:

    Solutions

    Mn > Cr > Fe > Co

    This order is also the order of decreasing stability of the oxidations states of the species involved.

    EoMn2+/Mn = -1.18 V

    EoCr2+/Cr = -0.56 V

    EoFe2+/Fe = -0.44 V

    EoCo2+/Co = -0.28 V

     

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