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SSC MTS 2024 Aptitude Test - 2
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SSC MTS 2024 Aptitude Test - 2
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  • Question 1/10
    3 / -0

    Three-fifths of my current age is the same as five-sixths of that of one of my cousins’. My age ten years ago will be his age four years hence. My current age is ______ years.

    Solutions

    Let my current age = x years and my cousin’s age = y years.

    Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

    ⇒ 3x/5 = 5y/6

    ⇒ 18x = 25y

    My age ten years ago will be his age four years hence,

    ⇒ x – 10 = y + 4

    ⇒ y = x – 14,

    ⇒ 18x = 25(x – 14)

    ⇒ 18x = 25x – 350

    ⇒ 7x = 350

    ∴ x = 50 years

  • Question 2/10
    3 / -0

    The given figures depicts the country-wise and age-wise distribution of people who visit China for business set-up.

    If in a given year, 500,000 people visited China, then the number of American nationals of the age group below 20 years who visited China is:

    Solutions

    Calculation:

    Now, the number of American nationals of the age group below 20 years who visited China

    ⇒ 500000 × 60% × 60%

    ⇒ 1,80,000

    ∴ The number of American nationals of the age group below 20 years who visited China is 1,80,000.

  • Question 3/10
    3 / -0

    A person travels from A to B at a speed of 30 km/h and returns at a speed of 45 km/h. What is the average speed in km/h during the whole journey?

    Solutions

    Given:

    From A to B, speed = d = 30 km/h

    From B to A, speed = p = 45 km/h

    Concept used:

    Average speed = 2dp/(d + p)

    Calculation:

    Average speed = (2 x 30 x 45)/(30 + 45)

    ⇒ 2700/75

    ⇒ 36

    Therefore, the correct answer is 36

  • Question 4/10
    3 / -0

    The speed of a train is 42 km/h. It crosses an electric pole in 27 seconds and a platform in 51 seconds. What is the length (in m) of the platform?

    Solutions

    Given:

    The speed of the train = 42 km/h

    Formula used:

     Where, S = Speed, D = Distance, and T = Time

    Calculation:

    Let the length of the platform be X m

    According to the question

  • Question 5/10
    3 / -0

    The ratio of age of alpha and beta is 2 ∶ 5. If the sum of their ages is 238, then find the difference between their age.

    Solutions

    Given:

    The ratio of alpha and beta to age is 2 ∶ 5.

    Sum of their ages is 238.

    Calculation:

    Let's assume the ages of alpha and beta are 2x and 5x, respectively, where x is a common multiplier.

    So, we can write the equation:

    2x + 5x = 238

    7x = 238

    Dividing both sides by 7:

    x = 238 / 7

    x = 34

    Now, we can find the ages of alpha and beta:

    Alpha's age = 2x = 2 * 34 = 68

    Beta's age = 5x = 5 * 34 = 170

    The difference between their ages is:

    170 - 68 = 102

    Therefore, the difference between the ages of alpha and beta is 102.

    ∴ Option 1 is the correct answer.

  • Question 6/10
    3 / -0

    81, 52, 29, 73, 48, 33, 31

    The median of the above data is

    Solutions

    Given:

    81, 52, 29, 73, 48, 33, 31

    Concept used: 

    If n is odd, the median is the middle value in the set:

    Calculation:

    On arranging the given data in decreasing order,

    ⇒ 81, 73, 52, 48, 33, 31, 29

    Total number of observation = 7

    ⇒ Median = 4th observation

    ⇒ Median = 48

    ∴ The median of the above data is 48.

  • Question 7/10
    3 / -0

    If the mean and median of a set of numbers are 8 and 11 respectively, then the mode will be:

    Solutions

    Given:

    Mean = 8

    Median = 11

    Concept used:

    Mode = 3 Median - 2 Mean

    Calculation:

    Mode = 3 × 11 - 2 × 8

    ⇒ Mode = 33 - 16

    ⇒ Mode = 17

    ∴ The mode is 17.

    ∴ Option 3 is the correct answer.

  • Question 8/10
    3 / -0

    The perimeter of a rectangle having area equal to 144 cm2 and sides in the ratio 4 ∶ 9 is

    Solutions

    Given:

    The perimeter of a rectangle having area equal to 144 cm2

    Sides are in the ratio 4 : 9

    Formula Used:

    Area of rectangle = l × b

    Perimeter of rectangle = 2(l + b)

    Calculation:

    Let, 'l' and 'b' are the sides of the rectangle.

    ⇒ b = 4x and l = 9x

    Area of rectangle = l × b

    ⇒ 144 = (4x) × (9x)

    ⇒ x = 2

    Now, b = 4 × 2 = 8 cm and l = 9 × 2 = 18 cm

    Perimeter of rectangle = 2(l + b)

    ⇒ 2(18 + 8) = 2 × 26 = 52 m

    Perimeter of rectangle = 52 m

    ∴ The perimeter of the rectangle is 52 m

  • Question 9/10
    3 / -0

    If selling price of an article is Rs. 432 and profit is 35%, then what will be the cost price of the article?

    Solutions

    GIVEN:

    Selling price of the article is Rs. 432

    Profit gained on the article is 35%

    FORMULA USED:

    Selling price = {1 + (Profit %) /100} × Cost Price

    CALCULATIONS:

    ⇒ 432 = {1 + (35/100)} × Cost Price

    ⇒ Cost Price = 432/ 1.35 = 320

    Hence, Cost price of the article is Rs. 320.

    Alternate solution

    Such questions can be solve easily by assuming Cost price 100x.

    Hence, profit = 35x and selling price = 135x

    According to question, 

    135x = 432

    ⇒ x = 432/135

    ∴ Cost price = 100x = (432/135) × 100 = 320.

  • Question 10/10
    3 / -0

    Interest earned after 5 years on ordinary interest of 12% per annum on a fixed amount is Rs. 5640. Find out the amount invested. (In rupees)

    Solutions

    Given:

    Ordinary interest rate = 12% per annum

    Time period = 5 years

    Interest earned = Rs. 5640

    Formula:

    Simple Interest S.I. = (PRT)/100

    where,

    P = Principal amount

    R = Rate of interest

    T = Time period

    Solution:

    Let P be the principal amount invested.

    Using the formula for simple interest, we have:

    ⇒ S.I. = (PRT)/100

    ⇒ 5640 = (P × 12 × 5)/100

    ⇒ 5640 = (60P)/100

    ⇒ 564000 = 60P

    ⇒ P = 9400

    Therefore, the amount invested is Rs. 9400.

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