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SSC Selection Post-XII 2024 (Matric) Aptitude Test - 10
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SSC Selection Post-XII 2024 (Matric) Aptitude Test - 10
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  • Question 1/10
    2 / -0.5

    A person saves 50% of his income. One year later, his income increases by 39% but he still saves the same amount of money. What is the percentage hike in his expenditure?

    Solutions

    Given:

    A person said 50% of his income.

    After 1 year his income increases by 39% but still he saves the same amount as before.

    Formula used:

    Income = expenditure + savings

    Calculations:

    Let income be Rs. 100

    He saves 50% of income = 50% × 100

    = 39 × 2 = 78%

    ∴ The answer is 78%.

  • Question 2/10
    2 / -0.5

    A man Distributed his wealth in the ratio (2/9) ∶ (3/7) ∶ (4/11) to his heirs named Aman, Bharat, and Chandu. If Chandu received Rs. 4284 as his share, then find the difference between share of Aman and Bharat.

    Solutions

    Given:

    Ratio of Sum of Aman, Bharat, and Chandu = (2/9) ∶ (3/7) ∶ (4/11)

    Share of Chandu = Rs. 4284

    Concept Used:

    We need to take the L.C.M. of denominator of given ratios and multiply that L.C.M. with ratios to get ratios in whole number.

    We need to equate the Ratios to their actual values.

    Calculation:

     L.C.M. of (9, 7, 11) i.e. 693

    Ratio = [(2/9) ∶ (3/7) ∶ (4/11)] × 693 = 154 ∶ 297 ∶ 252

    Share of Chandu = 252 Units

    ⇒ 252 Units = Rs. 4284

    ⇒ 1 Unit = 4284/252 = RS 17

    Difference between share of Aman and Bharat = (297 - 154) = 143 Units

    ⇒ Difference between share of Aman and Bharat = 143 × 17

    ⇒ Difference between share of Aman and Bharat = Rs. 2431

    ∴ The Difference between share of Aman and Bharat is Rs. 2431

  • Question 3/10
    2 / -0.5

    Three pipe x, y and z, where x and y are inlet pipe can fill an empty tank in 20 hours and 30 hours and z be the outlet pipe and can empty the tank in 60 hour, If all the pipes are opened, then in what time empty tank get full.

    Solutions

    Given:

    Inlet pipe x and y can fill an empty tank in 20 hours and 30 hours.

    Outlet pipe z can empty a full tank in 60 hours.

    Concept used:

    Time ∝ 1/Efficiency

    Calculation:

    The efficiency of pipe x is

    ⇒ x = 1/20

    The efficiency of pipe y is

    ⇒ y = 1/30

    The efficiency of pipe z will be negative because z is the outlet pipe

    ⇒ z = -1/60

    Together they will fill the tank in

    ⇒ 1/20 + 1/30 - 1/60

    ⇒ (3 + 2 - 1)/60

    ⇒ 4/60

    ⇒ 1/15

    ∴ Together they will fill the tank in 15 hours.

  • Question 4/10
    2 / -0.5

    The average weight of 6 men is 65.1667 kg, the average weight of 8 women is 78.125 kg and the average weight of 5 boys is 55.2 kg, Find the average weight per person. (in kg)

    Solutions

    Given:

    The average weight of 6 men = 65.1667 kg

    The average weight of 8 women = 78.125 kg

    The average weight of 5 boys = 55.2 kg

    Concept used:

    • The decimal to fraction conversion:

    • Average weight of n person = (Sum of weight of all n person)/(n number of persons)

    Calculation:

    According to the question,

    The average weight of 6 men = 65.1667 kg = 65 + 0.1667

  • Question 5/10
    2 / -0.5

    Solutions

  • Question 6/10
    2 / -0.5

    A vessel is fully filled with a special liquid. Four litres of liquid is drawn out of this vessel and is replaced with water. If the ratio of the special liquid to the water becomes 1 : 2, then what is the capacity the vessel?

    Solutions

    Given:

    Four litres of liquid is drawn out of this vessel and is replaced with water. The ratio of the special liquid to the water becomes 1 : 2

    Calculation:

    Let x be the quantity of special liquid filled in vessel

    ⇒ 4 litres drawn so new quantity will be = x – 4

    ⇒ Quantity of water added = 4 litres

    ⇒ Ratio = (x – 4)/4

    ⇒ 1/2 = (x – 4)/4

    ⇒ 2x – 8 = 4

    ⇒ x = 12/2 = 6

    ∴ capacity of the vessel is 6 lit.

  • Question 7/10
    2 / -0.5

    40 Workers can build a dam in 30 days. If 60 Workers are to be assigned to be complete the same work, then the number of days required will be:

    Solutions

    Given:

    40 workers can build a dam in 30 days

    60 workers are to be assigned to complete the same work

    Formula used:

    Efficiency = work done/Time taken

    Calculation:

    Let the number of days be x

    40 workers can build a dam in 30 days = 40 × 30

    ⇒ 1200

    Now,

    60 Workers are to be assigned to be complete the same work 

    ⇒ x = 1200/60

    ⇒ 20 days

    ∴ The number of days required will be 20

  • Question 8/10
    2 / -0.5

    A alone can complete a piece of work in 12 days. A and B together can complete it in 8 days. How long will B alone take to complete the work?

    Solutions

    Given:

    A alone can complete a piece of work in 12 days.

    A and B together can complete it in 8 days

    Formula:

    (A + B)’s 1 day work = 1/A + 1/B

    Calculations:

    A's 1 day's work = 1/12

    (A + B)'s 1 day's work = 1/8

    (A + B)'s 1 day's work = 1/12 + 1/B

    ⇒ 1/8 = 1/12 + 1/B

    ⇒ 1/8 – 1/12 = 1/B

    ⇒ 4/96 = 1/B

    ⇒ 1/B = 1/24

    ⇒ B = 24 Days

     B will finish the work in 24 days.

    Alternate Method

    Total work = LCM of 12 and 8 = 24

    ⇒ Total work = 24 units

    In 1 day A can do 24/12 = 2 unit work

    In 1 day A & B together can do 24/8 = 3 unit work

    ⇒ In 1 day B can do (3 - 2) = 1 unit work

    ⇒ To complete 24 unit work B alone will take 24/1 = 24 days

    ∴ B will finish the work in 24 days.

  • Question 9/10
    2 / -0.5

    When a 30% concentration of alcohol is mixed with an 80% concentration of alcohol we get a mixture of 50% concentration of alcohol. In what ratio were these two different concentrations of alcohol mixed?

    Solutions

    Given:

    When a 30% concentration of alcohol is mixed with an 80% concentration of alcohol we get a mixture of 50% concentration of alcohol. 

    Formula:

    Mixture and Allegation method:

    Calculation:

    According to the above formula

    Required ratio = 30 ∶ 20 = 3 ∶ 2

    ∴ The required ratio is 3 ∶ 2.

  • Question 10/10
    2 / -0.5

    What is the difference in the total interest obtained on Rs. 10000 at the rate of 10% for a period of 2 years when the amount is compounded semi-annually and bi-annually?

    Solutions

    If an amount P is compounded at interest rate of r for T years then the total amount which we will get

    And the compound interest which we will obtain

    When the interest is compounded semiannually means, interest is added to principal amount every 6 month. In this case time cycle = 2 × 2 = 4 and effective rate = 10/2 = 5%

    Now interest obtained in this case = 10000(1 + 5/100)4 – 10000 = 12155 – 10000 = Rs 2155

    Now when interest is compounded biannually then in this case time cycle = 2/2 = 1 and effective rate = 10 × 2 = 20%

    Now interest obtained in this case = 10000(1 + 20/100) – 10000 = 12000 – 10000 = Rs 2000

    So the difference is,   2155 – 2000 = Rs 155.

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