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SSC Selection Post-XII 2024 (HS) Aptitude Test - 9
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SSC Selection Post-XII 2024 (HS) Aptitude Test - 9
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  • Question 1/10
    2 / -0.5

    A cistern has two pipes A and B. A can fill it in 16 minutes and B can fill it in 20 minutes. If another pipe C can empty it in 40 min, then how much time will it take for the cistern to be filled, if all the pipes are opened at the same time?

    Solutions

    Total capacity of Cistern = LCM of 16, 20 and 40 = 80 units

    Efficiency of A = 80/16 = 5 units/min

    Efficiency of B = 80/20 = 4 units/min

    Efficiency of C = - 60/40 = - 2 units/min

    Efficiency of A, B and C together = 5 + 4 - 2 unit/min = 7 units/min

  • Question 2/10
    2 / -0.5

    If the speed of a train is increased by 20%, its travel time between two stations reduces by 2 hrs. If its speed is decreased by 20%, the travel time increases by 3 hrs. What is the normal duration of travel (in hrs)?

    Solutions

    Concept:

    distance travel by a train with speed s for time t is d = s × t

    Explanation:

    Let d be the distance, s be the speed and t be the time

    If the speed of a train is increased by 20%, its travel time between two stations reduces by 2 hrs.

    12(t - 2) = 8(t + 3)

    3(t - 2) = 2(t + 3)

    3t - 6 = 2t + 6

    t = 12

    the normal duration of travel = 12 hr

    Option (2) is correct.

  • Question 3/10
    2 / -0.5

    There are 12 friends A, B, C, D, E, F, G, H, I, J, K and L who invested money in some business in the ratio of 1 : 2 : 3 : 4 : 5 : 6 : 7 : 8 : 9 : 10 : 11 : 12 and the duration for which they invested the money is in the ratio of 12 : 11 : 10 : 9 : 8 : 7 : 6 : 5 : 4 : 3 : 2 : 1 respectively. Who will get the maximum benefit at the end of the year?

    Solutions

    Ratio in which the profit will be shared = Investment × Time for which investment was made

    ⇒ (1 × 12) : (2 × 11) : (3 × 10) : (4 × 9) : (5 × 8) : (6 × 7) : (7 × 6) : (8 × 5) : (9 × 4) : (10 × 3) : (11 × 2) : (12 × 1)

    ⇒ 12 : 22 : 30 : 36 : 40 : 42 : 42 : 40 : 36 : 30 : 22 : 12

    Here we can see that shares of both F and G in the profit will be maximum.

  • Question 4/10
    2 / -0.5

    A person bought an article and sold it at a profit of 20%. Had he bought it at 20% less, what would have been the profit percentage if the selling price had been the same?

    Solutions

    Concept Used:

    SP = CP + Profit

    Profit% = (Profit/CP) × 100

    CP = Cost Price, SP = Selling Price

    Calculation:

    A person bought an article and sold it at a profit of 20%:

    Let's consider CP1 is 100.

    ⇒ SP = 100 + 100 × (20/100) = 120

    Had he bought it at 20% less:

    ⇒ CP2 = 100 - 100 × (20/100) = 80

    Since he still sells it at the same selling price of 120,

    ⇒ Profit = 120 - 80 = 40

    ⇒ Profit% = (40/80) × 100 = 50%

    ∴ The Profit Percentage is 50%.

    Shortcut Trick

    ⇒ SP / CP = (100 + 20) / (100 - 20)

    ⇒  SP / CP = 120 / 80

    ⇒ Profit% = [(120 - 80) × 100] / 80 

    ⇒ 400 / 80 = 50% 

    ∴ The profit percentage is 50%.

  • Question 5/10
    2 / -0.5

    Directions For Questions

    The following graph gives information about the death rate due to dengue fever in tribal village 'Z' for the last 6 years.

    ...view full instructions


    What is the number of deaths due to dengue in village 'Z' during the years 2014 and 2015 together?

    Solutions

    The logic followed is:

    Thus the total number of deaths due to dengue in village 'Z' in the years 2014 and 2015 are:

    15 + 10

    = 25

    Hence, the correct answer is "25".

  • Question 6/10
    2 / -0.5

    Intercity train covers a certain distance in 45 min. If its speed is reduced by 5 km/hrs, it takes 3 min more to cover the same distance. What will be the distance (in km):

    Solutions

    Given:

    time taken by intercity train =  45 minutes

    Concept Used:

    speed is inversely proportional to time when distance is same

    Calculation:

    ⇒ Ratio of time taken = 45 : 48 = 15 : 16

    ⇒ Ratio of speed = 16 : 15

    ⇒ 1 units ratio = 5 km/hrs.

    ⇒ 16 units ratio = 80 km/hrs.

    ∴ Distance = 80 × 45/60 = 60 km

  • Question 7/10
    2 / -0.5

    A man spends 25% on food, 30% on house rent, 11% on travel, and 19% on education. After all these expenditures he saved Rs. 8760. Find the amount spent on travel.

    Solutions

    Given:

    Spent on food = 25%

    Spent on house rent = 30%

    Spent on travel = 11%

    Spent on Education = 19%

    Calculation:

    Let the total income be Rs. X.

    Total expenditure = X × (25% + 30% + 11% + 19%)

    ⇒ (X × 85%)

    Total Saving = [X - (X × 85%)]

    ⇒ (X × 15%)

    According to question,

    (X × 15%) = Rs. 8760

    ⇒ X = Rs. [(8760 × 100)/15]

    ⇒ Rs. (584 × 100)

    ⇒ Rs. 58400

    So, Expenditure on travel = 11% of Rs. 58400

    ⇒ (11/100) × Rs. 58400

    ⇒ Rs. 6424

    ∴ The amount spent on travel is Rs. 6424.

    Alternate Method

    Total Income = 100%

    Total expenditure = (25% + 30% + 11% + 19%)

    Savings = [100% - (25% + 30% + 11% + 19%)]

    ⇒ 15%

    Expenditure on Travel = Rs. [(8760/15) × 11]

    ⇒ Rs. 6424.

    ∴ The amount spent on travel is Rs. 6424.

  • Question 8/10
    2 / -0.5

    Ben invested Rs.10000 at 20% for 2 years compounded annually. Joe invested the same amount for same time and same time period but it was at simple interest. Find the difference between the interests earned by Ben and Joe.

    Solutions

    Given:

    P = 10000

    R = 20%

    T = 2 years

    Formula used:

    Where,

    A = Amount

    CI = Compound interest

    SI = Simple interest

    P = Principal amount

    R = Rate of interest

    T = Time period

    Calculations:

    Joe’s interest = SI = (10000 × 20 × 2)/100

    ⇒ 1000 × 4

    ⇒ Rs.4000

    Ben’s interest = CI = 10000 × [1 + (20/100)]2 – 10000

    ⇒ 10000 × [(6/5)2 – 1]

    ⇒ 10000 × (36 - 25)/25

    ⇒ 400 × 11

    ⇒ Rs.4400

    ⇒ Difference in interests = Rs. 4400 – Rs. 4000 = Rs. 400

    ∴ The difference between the interests earned by Ben and Joe is Rs.400

    Alternate Method

    Convert percentage into fraction

    20% = 1/5

    ⇒ SI = 2000 + 2000 = 4000

    ⇒ CI = 2000 + 2000 + 400 = 4400

    ⇒ CI – SI = 400

    ∴ Difference between the interests is Rs.400

  • Question 9/10
    2 / -0.5

    A sum of Rs. 12,000 deposited at compound interest becomes double after 5 years. After 20 years, it will become

    Solutions

    For compound interest:

    Where,

    A = Amount

    P = Principal

    R = rate %

    t = time in years

    Given, A sum of Rs. 12,000 deposited at compound interest becomes double after 5 years.

    P = 12000

    A = 2 × P = 24000

    t = 5 years

    R = ?

    Substituting from eq 1 we have

    ⇒ A = 12000 × 24

    ⇒ A = 12000 × 16

    ⇒ A = Rs. 192000

  • Question 10/10
    2 / -0.5

    Directions For Questions

    Directions: Using the data from the graph answer the question below:

    Find the total number of males from sector P and females from sector R together.

    ...view full instructions


    The ratio of the number of male and female employees

    Solutions

    Given:

    The number of employees working in five sectors and the respective ratio of males and females are given.

    Calculations:

    Number of employees in P sector = 650

    The number of male employees and female employees in P sector be 6x and 7x

    Total employees = (6x + 7x) = 13x

    Number of male employees in P sector = 650 × 

    ⇒ 6 × 50 = 300

    Number of employees in R sector = 850

    The number of male employees and female employees in R sector be 9x and 8x

    Total employees = (9x + 8x) = 17x

     

    Number of female employees in R sector = 850 × 

    ⇒ 8 × 50 = 400

    Required total male employees from P sector and female employees from R sector

    ⇒ (300 + 400) = 700

    ∴ The answer is 700.

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