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Correct answer is option B
Let the number is x
Twice of a number = 2x
Reciprocal of a number x is
Thrice of its reciprocal
We have to find the number x, Sum of
Number should be x = 6
Correct Answer is option D
Let three consecutive integer is a – 1, a, a + 1
Sum = a – 1 + a + a + 1 =81
3a = 81
a = 27
so, middle number is a, a = 27
x = 43 × 19 – 21 ÷ 5 × 31 + 23.7
x = 817 – 4.2 × 31 + 23.7
x = 840.7 – 130.2 = 710.5
hence, 370 < x < 720
x = 28 × 50 ÷ 35 – 12 × 143 ÷ 44 + 1077
x = 40 – 39 + 1077
x = 1078
Now, y = √x = √1078
We know, √1024 = 32 and √1089 = 33
Hence, y lies between 32 and 33.
Only option D satisfies this condition.
Given there are two natural numbers whose sum is 171 and whose least common multiple is 266
Prime factorisation of 266 =
As sum of two numbers is 171.
So we will now try to form possible pairs of required numbers using LCM.
Possible pairs are: (14,19), (14,38), (14,133), (38,133)
But their sum if 171.
So required numbers are 38 and 133
Correct (-)
Wrong (-)
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