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The downstream speed of a boat is 17 km/hr and the speed of current is 2 km/hr. What is the total time (in hours) taken by the boat to cover 65 km upstream and 170 km downstream?
Let the speed of boat in still water be u km/hr.
The speed of current = v = 2 km/hr
⇒ The downstream of boat = u + v = 17 km/hr
⇒ The speed of boat in still water = u = 17 - 2 = 15 km/hr
⇒ The upstream of boat = u - v = 15 - 2 = 13 km/hr
We know that,
Time = Distance/Speed
If m ∶ n = 2 ∶ 3 and x ∶ y = 4 ∶ 5, then the value of 10mx + 4ny ∶ 5mx + 3ny is __________.
Given:
m ∶ n = 2 ∶ 3
x ∶ y = 4 ∶ 5
Solution:
Let m = 2a and n = 3a
x = 4b and y = 5b
Putting the above value in the given expression, we will get:
⇒ 10mx + 4ny ∶ 5mx + 3ny
⇒ (10 × 2a × 4b) + (4 × 3a × 5b) ∶ (5 × 2a × 4b) + (3 × 3a × 5b)
⇒ (80ab) + (60ab) : (40ab) + (45ab)
⇒ 140ab : 85ab = 28 : 17
In the following figure, if PT = 12 cm and PB = 24 cm, then find AB.
Formula Used:
From the tangent theorem,
PT2 = PA x PB
Calculations:
⇒ Here, PT = 12 cm
⇒ PB = 24 cm
Now put the value of PT and PB
⇒ PT2 = PA x PB
⇒ 122 = PA x 24
⇒ PA = 144 / 24 = 6 cm
As we know,
⇒ PB = PA + AB
⇒ AB = PB - PA = 24 - 6 = 18 cm
⇒ Hence, The value of AB is 18 cm.
Gorang worked h on Monday, 190 min on Tuesday, from 5:20 am to 9:10 am on Wednesday and 220 min on Friday. He is paid Rs. 42 per hour. How much did he earn from Monday to Friday?
Total time taken by Gorang for doing work
= Monday + Tuesday + Wednesday + Friday
A seller offers a 17% discount on a TV set with a marked price of Rs. 5600. If he still earns a profit of Rs. 500, then what is the cost price of the TV set?
Short trick:
Cost price = 5600 × 83/100 - 500 = Rs. 4148
Detailed solution:
Marked price of TV set = Rs. 5600
Discount = 17%
Selling Price of TV set after discount,
= 5600 - 5600 × (17/100)
= 5600 - 56 × 17
= 5600 - 952
= 4648
Selling price of TV set = Rs. 4648
Profit earned (given) = Rs. 500
Profit = S.P - C.P
⇒ 500 = 4648 - C.P
⇒ C.P = 4148
∴ Cost price of TV set is Rs. 4148.
Thus, the correct answer is option 2.
The surface area of a cuboid having length 6 cm, breadth 7 cm and height 8 cm is:
A cuboid having length 6 cm, breadth 7 cm and height 8 cm
Concept used:
Surface area = 2(LB + BH + HL)
Calculation:
⇒ Surface area = 2[(6 x 7) + (7 x 8) + (8 x 6)]
⇒ 2(42 + 56 + 48)
⇒ 2 x 146
⇒ 292 cm2
∴ The surface area of a cuboid having length 6 cm, breadth 7 cm and height 8 cm is 292 cm2
Jay takes a loan of Rs 10,000 from Amit at 5% simple interest for 2 years. He also takes the same amount at the same rate and the same time from Mukesh at compound interest. Find the difference in the interest paid by Jay shah.
Amount of money taken on Loan by Jay = Rs 10,000.
Rate of interest = 5%
Time = 2 years.
Concept:
Simple interest = ((P × R × T)/100)
Equivalent Rate on Compound interest = ( X + Y + ((X × Y)/100)
Equivalent Rate on Compound interest = ( 5 + 5 + ((5 × 5)/100) = 10.25%
Total simple interest on Rs 10000 at 5% for 2 years = (10,000 × 10%) = Rs 1000
Total Compound interest on Rs 10000 at 5% for 2 years = (10,000 × 10.25%) = Rs 1025
Difference in the Interest paid = Rs 25
Three people A, B, and C invested a total amount of Rs. 38000 in a startup business. Their investment time is in the ratio of 2 : 5 : 3. After 1 year they received a profit share of Rs. 24000, Rs. 35000 and Rs. 57000 respectively. What is the ratio of their amount of investment?
GIVEN:
A received Rs. 24000
B received Rs. 35000
C received Rs. 57000
FORMULA:
Profit Share ratio = Investment Amount × Investment Time
CALCULATION:
Let the ratio of money investment be x : y : z
⇒ Ratio of profit share = 2x : 5y : 3z
According to the question
2x : 5y : 3z = 24000 : 35000 : 57000 = 24 : 35 : 57
⇒ x : y : z = 12 : 7 : 19
If the ratio of the radii of two circles is 2 : 3, then the ratio of their circumference is
The ratio of the radius of the two circles = 2 : 3
Formula used:
The circumference of the circle = 2 × π × r (Where, r = The radius of the circle)
Let be assume the radius of the circles is 2p and 3p respectively
⇒ The circumference of the first circle = 2 × π × (2p)
⇒ The circumference of the second circle = 2 × π × (3p)
⇒ The required ratio of the circumferences = { 2 × π × (2p)}/{2 × π × (3p)} = 2 : 3
∴ The required result will be 2 : 3.
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