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Quant - Quadratic Test 488
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Quant - Quadratic Test 488
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  • Question 1/5
    1 / -0.25

    Directions For Questions

    Direction: In the following question two equations are given in variables x and y. You have to solve these equations and determine the relation between x and y.

    ...view full instructions


    I. 2x2+ 3x – 20 = 0      

    II. 2y2 – y – 21 = 0

    Solutions

    I. 2x2+ 3x – 20 = 0

    ⇒ 2x2+ 8x – 5x – 20 = 0

    ⇒ 2x(x + 4) – 5(x + 4) = 0

    ⇒ (2x – 5)(x + 4) = 0

    ⇒ x = –4 and 2.5

    II. 2y2 – y – 21 = 0

    ⇒ 2y2 + 6y – 7y – 21 = 0

    ⇒ 2y(y + 3) – 7(y + 3) = 0

    ⇒ (y + 3)(2y – 7) = 0

    ⇒ y = –3 and 3.5

    ∴ No relationship can be established between x and y.

  • Question 2/5
    1 / -0.25

    Directions For Questions

    Direction: In the following question two equations are given in variables x and y. You have to solve these equations and determine the relation between x and y.

    ...view full instructions


    I. x− 12x + 35 = 0     

    II. y− 13y + 40 = 0

    Solutions

    I. x− 12x + 35 = 0

    ⇒ (x− 5x) – (7x − 35) = 0

    ⇒ x(x − 5) – 7(x − 5) = 0

    ⇒ (x − 7)(x − 5) = 0

    ⇒ x = 5 and 7

    II. y− 13y + 40 = 0

    ⇒ (y– 5y) – (8y – 40) = 0

    ⇒ y(y – 5) – 8(y – 5) = 0

    ⇒ (y − 5)(y – 8) = 0

    ⇒ y = 5 and 8
    Now, (x = 5) < (y = 8)
    And, (x = 7) > (y = 5)

    Thus, no relationship can be established between x and y.

  • Question 3/5
    1 / -0.25

    Directions For Questions

    Direction: In the following question two equations are given in variables X and Y. You have to solve these equations and determine the relation between X and Y.

    ...view full instructions


    I. x2 + 6x 55 = 0     

    II. y2 5y – 36 = 0

    Solutions

    x2 + 6x 55 = 0

    (x2 5x) + (11x 55) = 0

    x(x 5) + 11(x 5) = 0

    (x + 11)(x 5) = 0

    x = 5 and −11

    y2 5y – 36 = 0

    (y2+ 4y) – (9y + 36) = 0

    y(y + 4) – 9(y + 4) = 0

    (y + 4)(y – 9) = 0

    y = 9 and −4

    No relationship can be established between x and y.

  • Question 4/5
    1 / -0.25

    Directions For Questions

    Direction: In the following question two equations are given in variables X and Y. You have to solve these equations and determine the relation between X and Y.

    ...view full instructions


    I. x2 + 12x + 35 = 0  

    II. y2 + y - 20 = 0

    Solutions

     x2 + 12x + 35 = 0

    (x2 + 7x) + (5x + 35) = 0

     x(x + 7) + 5(x + 7) = 0

     (x + 5)(x + 7) = 0

     x = –7, –5

    y2 + y - 20 = 0

     (y2 - 4y) + (5y - 20) = 0

     y(y- 4) + 5(y - 4) = 0

     (y + 5)(y - 4) = 0

     y = 4 and –5

    ∴ x ≤ y

  • Question 5/5
    1 / -0.25

    Directions For Questions

    Direction: In the following question two equations are given in variables x and y. You have to solve these equations and determine the relation between x and y.

    ...view full instructions


    I.  x2 – 14x + 48 = 0  

    II. y2 + 14y + 48 = 0

    Solutions

     x2 – 14x + 48 = 0

     (x2- 6x) - (8x - 48) = 0

     x(x - 6) - 8(x - 6) = 0

     (x - 6)(x - 8) = 0

     x = 6 and 8

    y2 + 14y + 48 = 0

     (y2 + 6y) + (8y + 48 ) = 0

     y(y+6) + 8(y + 6) = 0

     (y + 6)(y + 8) = 0

     y = –6 and –8

    ∴ x > y

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