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Directions For Questions
Direction: Study the following graph carefully to answer the questions.
Number (in thousands) of Products Manufactured and Sold by a Company Over the Years.
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What is the respective ratio of the number of products not sold by the company in the year 2007 to those not sold in the year 2005?
Required ratio = (45 – 42.5) : (37.5-30)
= 2.5 : 7.5
= 1 : 3
What is the approximate average number of products manufactured by the company over all the years together?
Required average
In the following number series only one number is wrong. Find out the wrong number.
112, 89, 68, 53, 40, 29
The pattern of the series is:
112 – 23 = 89
89 – 19 = 70
70 – 17 = 53
53 – 13 = 40
40 – 11 = 29
Hence, the incorrect number is 68.
903, 911, 935, 970, 1031, 1103
Pattern of the series is:
903 + (8 × 1) = 911
911 + (8 × 3) = 935
935 + (8 × 5) = 975
975 + (8 × 7) = 1031
1031 + (8 × 9) = 1103
Clearly 970 is the wrong number.
In the following number series, only one number is wrong. Find out the wrong number.
14, 15, 16, 46, 62, 187
14 + 13 = 15
15 + 22 = 19
19 + 33 = 46
46 + 42 = 62
62 + 53 = 187
5, 5, 7.5, 13.5, 37.5, 112.5
5 × 1 = 5
5 × 1.5 = 7.5
7.5 × 2 = 15
15 × 2.5 = 37.5
37.5 × 3 = 112.5
Find the wrong term in the given series.
67.5, 80, 105, 155, 250, 455
Pattern: - 12.5, - 25, - 50, - 100, - 200
The number should be 250.
67.5, 80, 105, 155, (255), 455
In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.
I. x2 – 6x – 16 = 0
II. y2 – 19y + 88 = 0
⇒ x2 – 8x + 2x – 16 = 0
⇒ x(x – 8) + 2(x – 8) = 0
⇒ (x – 8)(x + 2) = 0
⇒ x = 8, – 2
⇒ y2 – 8y – 11y + 88 = 0
⇒ y(y – 11) – 8(y – 11) = 0
⇒ (y – 8)(y – 11) = 0
⇒ y = 8, 11
So, x ≤ y.
Hence, option B is correct.
⇒ x = 41
II. y2 – 881 = 800
⇒ y2 = 800 + 881
⇒ y2 = 1681
⇒ y = ± 41
So, x ≥ y.
Hence, option D is correct.
In the following question two equations are given in variables x and y. You have to solve these equations and determine relation between x and y.
I. x2 + 7x + 12 = 0
II. y2 + 5y + 6 = 0
x2 + 7x + 12 = 0
⇒ x2 + 4x + 3x + 12 = 0
⇒ x(x + 4) + 3(x + 4) = 0
⇒ (x + 3) (x + 4) = 0
⇒ x = −3, −4
y2 + 5y + 6 = 0
⇒ y2 + 2y + 3y + 6 = 0
⇒ y(y + 2) + 3(y + 2) = 0
⇒ (y + 3) (y + 2) = 0
⇒ y = −3, −2
Thus, x ≤ y
Correct (-)
Wrong (-)
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