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Let the age of Ram be 7x.
Therefore, Shivam’s age =9x
A.T.Q.
⇒
⇒ 49x – 84 = 45x - 60
⇒ 4x = 24
⇒ x = 6
Present age of Ram = 7x = 42 years
Present age of Shivam = 9x = 54 years
Required Ratio of ages after 12 years
= 9 : 11.
The Present ages of A and B are in the ratio 3: 1. Fifteen years hence, the ratio will be 2: 1. Their present age (in years) are
Lets B Present age is x
A’s present age = 3 x years B’s present age = x years After 15 years, ∴ A’s present age = 15×3 = 45 years
Let the age of father and his two sons be x, y and z years.
According to question:
x = 3 (y +z) ……………. (1)
20 years hence,
Fathers age = (x + 20)
And age of his two sons will be (y + 20) and (z + 20) years
(x+ 20) = (y + 20) + (z+ 20)
x + 20 = y + z + 40
x - (y + z) = 20 …………. (2)
putting the value of x in above equation (2):
we get
3 (y + z) – (y + z) = 20
2 (y + z) = 20
y + z = 10
putting the value of (y + z) in equation (1)
x = 3 × 10 = 30 years
12 years ago, the age of the mother was three times the age of her son. Say, the age of the son was 'x', and the mother's age was '3x'.
At present: Mother's age is (3x+12) and the son’s age is (x+12)
After ten years: The mother's age will be (3x+12)+10 and the son’s age will be (x+12)+10
Given that, mother’s age is twice that of son after ten years.
(3x+12)+10 = 2[(x+12)+10]
(3x+22) = 2(x+22)
Solving the equation, we get x = 22
Ratio of Present ages = (3x+12) : (x+12) = 78 : 34 = 39 : 17
Then the age of Rahul was: 45−x
His age when the son was born should be equal to .
Let Age of Ravi and Mohan be 9x and 7x respectively.
Age ratio of Mohan and Ram = 5 : 7
Age of Ram Age of Mohan =
Age ratio of Ram and Shyam
Age of Shyam Age of Ram
⇒ 57x = 114
⇒ x = 2
So, Age of Mohan = 7x = 14
Given that,
Kalim’s age = Pavan’s age + 16
Pavan’s age = Kalim’s age – 16
Given that, Kalim’s age = 3 × Chhotu’s age
9 × Chhotu’s age – 36 = 5 × Chhotu’s age
Chhotu’s age = 9 years
Kalim’s age = 3 × 9 = 27 years
Pavan’s age = 27 – 16 = 11 years
So, Pavan 4 years hence age = 11 + 4
= 15 years.
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