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We know that:
96, 110, and 146 make a Pythagoras triplet.
Area of a right angle triangle =
=
= 5280 m2
Therefore, required cost of levelling the field = 5280 × 5.60 = 29568 Rs.
Hence, option D is correct.
Let bigger side of rectangle be 4x cm.
Then, smaller side = (4x) × = 3x cm
Area of rectangle = 192 cm2 (given)
⇒ (4x) × (3x) = 192
⇒ 12x2 = 192
⇒ x2 = 192/12 = 16
⇒ x = = 4
Now, bigger side = 4 × 4 = 16 cm
And smaller side = 3 × 4 = 12 cm
Now, diagonal of rectangle (diameter of circle) =
= 20 cm
Perimeter of circle = 2πr = 20π cm
The inner and outer radii of two concentric circles are 6.7 cm and 9.5 cm, respectively as shown in figure:
Difference between their circumferences =
∴ Ratio of area of two triangles
= (√5)2 : (√7)2
= 5 : 7
Hence, option A is the correct answer.
(Take )
Let the radius of circle be r metre
According to question,
Cost of fencing = 2420
⇒ 2πr × 11 = 2420
⇒ = 220
⇒ r = 35 m
Area of the field = πr2 = = 3850 m2
Let the sides are 3x, 4x and 5x
Now, according to question,
5x – 3x = 3.6
2x = 3.6
x = 1.8 cm
Therefore, sides are 3x, 4x and 5x = 5.4cm, 7.2cm and 9cm
All three sides make a Pythagoras triplet, hence it is a right angle triangle
Area of right angle triangle =
= 19.44 cm2
Side of equilateral triangle = 16 cm
Area of equilateral triangle = Side2
= = cm2
"Hence, option A is the correct answer."
Breadth of a rectangle = y unit
Area of a rectangle =
If length of a rectangle is increased to its three times and breadth is decreased to its half, then
New length of a rectangle = 3x unit
New breadth of a rectangle = unit
Area of a rectangle = =
Required ratio =
Let the radius of two circles are r1 and
r1 + = 286 cm …..eq1
area between two concentric circles =
50336 =
= 50336 ×
() () = 16016
() =
() = 56 …..eq2
By adding both eq1 and eq2
r1 + + = 286 + 56
2 = 342
= 171 cm
By putting value of in eq1
171 + = 286
= 286 – 171
= 115 cm
Therefore, radii of two circles are 171 cm and 115 cm.
Area of room = Length × Width
= 12 × 8 = 96 cm2
The number of square designs required = = 6
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