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Mensuration - 2D Test 361
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Mensuration - 2D Test 361
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  • Question 1/10
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    The sides of a triangular field ar 96 m, 110 m and 146 m. The cost of levelling the field at Rs. 5.60 per m2 is:
    Solutions

    We know that:

    96, 110, and 146 make a Pythagoras triplet.

    Area of a right angle triangle =

    =

    = 5280 m2

    Therefore, required cost of levelling the field = 5280 × 5.60 = 29568 Rs.

    Hence, option D is correct.

  • Question 2/10
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    A circle circumscribes a rectangle whose sides are in the ratio of 4 : 3 . If the area of the rectangle is 192 cm2, then the perimeter (in cm) of the circle is:
    Solutions

    Let bigger side of rectangle be 4x cm.

    Then, smaller side = (4x) ×  = 3x cm

    Area of rectangle = 192 cm2 (given)

    (4x) × (3x) = 192

    12x2 = 192

    x2 = 192/12 = 16

    x =  = 4

    Now, bigger side = 4 × 4 = 16 cm

    And smaller side = 3 × 4 = 12 cm

    Now, diagonal of rectangle (diameter of circle) =

     = 20 cm

    Perimeter of circle = 2πr = 20π cm

  • Question 3/10
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    The inner and outer radii of two concentric circles are 6.7 cm and 9.5 cm, respectively. What is the difference between their circumferences (in cm)? Take .
    Solutions

    The inner and outer radii of two concentric circles are 6.7 cm and 9.5 cm, respectively as shown in figure:

    Difference between their circumferences =

  • Question 4/10
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    If the ratio of corresponding sides of two similar triangles is √5 : √7 then what is the ratio of the area of the two triangles?
    Solutions
     We know that, the ratio of areas of two similar triangle is equal to the ratio of square of their corresponding sides.

    Ratio of area of two triangles

    = (√5)2 : (√7)2

    = 5 : 7

    Hence, option A is the correct answer.

  • Question 5/10
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    A field is in the form of a circle. The cost of fencing around it at Rs. 11 per metre is Rs. 2,420 . What is the area (in m2) of the field?

    (Take )

    Solutions

    Let the radius of circle be r metre

    According to question,

    Cost of fencing = 2420

    2πr × 11 = 2420

     = 220

    r = 35 m

    Area of the field = πr2 =  = 3850 m2

    Hence, option A is the correct answer.

  • Question 6/10
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    The lengths of three sides of a triangle are in the ratio 3 : 4 : 5. Among three sides, the difference between the largest side and the smallest side of this triangle is 3.6 cm. The area (in cm2) of the triangle is:
    Solutions

    Let the sides are 3x, 4x and 5x

    Now, according to question,

     5x – 3x = 3.6

     2x = 3.6

     x = 1.8 cm

    Therefore, sides are 3x, 4x and 5x = 5.4cm, 7.2cm and 9cm

    All three sides make a Pythagoras triplet, hence it is a right angle triangle

    Area of right angle triangle =

    =

    = 19.44 cm2

  • Question 7/10
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    If the side of an equilateral triangle is 16 cm, then what is its area?
    Solutions

    Side of equilateral triangle = 16 cm

    Area of equilateral triangle =  Side2

    =  =  cm2

    "Hence, option A is the correct answer."

  • Question 8/10
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    If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
    Solutions
    Let length of a rectangle = x unit , and

    Breadth of a rectangle = y unit

    Area of a rectangle =

    If length of a rectangle is increased to its three times and breadth is decreased to its half, then

    New length of a rectangle = 3x unit

    New breadth of a rectangle =  unit

    Area of a rectangle =  =

    Required ratio =

  • Question 9/10
    1 / -0.25

    The sum of the radii of two circles is 286 cm and the area between the concentric circles is 50336 cm2. What are the radii (in cm) of the two circles? Take .
    Solutions

    Let the radius of two circles are r1 and

    Now, according to question,

     r1 +  = 286 cm …..eq1

    area between two concentric circles =

     50336 =

     50336 =

      = 50336 ×

     () () = 16016

     () =

     () = 56 …..eq2

    By adding both eq1 and eq2

     r1 +  +  = 286 + 56

     2 = 342

      = 171 cm

    By putting value of in eq1

     171 +  = 286

      = 286 – 171

      = 115 cm

    Therefore, radii of two circles are 171 cm and 115 cm.

  • Question 10/10
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    Flooring of a room 12 m long and 8 m wide is to be designed by squares of maximum possible area. Find the number of square designs required.
    Solutions

    Area of room = Length × Width

    = 12 × 8 = 96 cm2

    The number of square designs required =  = 6

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