Solutions
Given:
The given number = 957x5y6z3
Concept used:
Divisibility rule of 3: The sum of all digits of a number is divisible by 3 then the number is divisible by 3
Divisibility rule of 11: The provided integer is divisible if the difference between the sum of the digits at odd places and the sum of the digits at even places is 0 or divisible by 11
Calculation:
957x5y6z3 is divisible by 33
⇒ 957x5y6z3 is divisible by 3 and 11
⇒ (9 + 5 + 7 + x + 5 + y + 6 + z + 3) is divisible by 3
⇒ (35 + x + y + z) is divisible by 3 .................... (1)
Now check which option will be satisfied.
If x + y + z = 24 then (35 + x + y + z) = 35 + 24 = 59 → Not divisible by 3
If x + y + z = 27 then (35 + x + y + z) = 35 + 27 = 62 → Not divisible by 3
If x + y + z = 25 then (35 + x + y + z) = 35 + 25 = 60 → Divisible by 3
If x + y + z = 26 then (35 + x + y + z) = 35 + 26 = 61 → Not divisible by 3
So, only one option is being satisfied.
∴ The maximum value of (x + y + z) is 25
Alternate Method
According to the divisibility rule of 11
⇒ 9 + 7 + 5 + 6 +3 = 5 + x + y + z
x + y + z = 25