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SSC CHSL 2023 Aptitude Test - 5
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SSC CHSL 2023 Aptitude Test - 5
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  • Question 1/10
    2 / -0.5

    The ratio of length and breadth of a rectangle is 5 : 2 and the perimeter is 70 cm. What is the area of the rectangle?

    Solutions

    The perimeter of rectangle = 2(l + b), where l and b are length and breadth respectively.

    Let the ratio of l ∶ b = 5x ∶ 2x

    Perimeter of rectangle = 2(5x + 2x) 

    ⇒ 14x = 70

    ⇒ x = 5

    Hence, length = 5x = 25 cm and breadth= 2x = 10 cm

    Area of rectangle = l × b = 25 × 10 = 250 cm2

  • Question 2/10
    2 / -0.5

    If the 9-digit number 957x5y6z3 is divisible by 33, then what is the maximum value of (x + y + z)?

    Solutions

    Given:

    The given number = 957x5y6z3

    Concept used:

    Divisibility rule of 3: The sum of all digits of a number is divisible by 3 then the number is divisible by 3

    Divisibility rule of 11: The provided integer is divisible if the difference between the sum of the digits at odd places and the sum of the digits at even places is 0 or divisible by 11

    Calculation:

    957x5y6z3 is divisible by 33

    ⇒ 957x5y6z3 is divisible by 3 and 11

    ⇒ (9 + 5 + 7 + x + 5 + y + 6 + z + 3) is divisible by 3

    ⇒ (35 + x + y + z) is divisible by 3 .................... (1)

    Now check which option will be satisfied.

    If x + y + z = 24 then (35 + x + y + z) = 35 + 24 = 59 → Not divisible by 3

    If x + y + z = 27 then (35 + x + y + z) = 35 + 27 = 62 → Not divisible by 3

    If x + y + z = 25 then (35 + x + y + z) = 35 + 25 = 60 → Divisible by 3

    If x + y + z = 26 then (35 + x + y + z) = 35 + 26 = 61 → Not divisible by 3

    So, only one option is being satisfied.

    ∴ The maximum value of (x + y + z) is 25

    Alternate Method

    According to the divisibility rule of 11

    ⇒ 9 + 7 + 5 + 6 +3 = 5 + x + y + z

    x + y + z = 25

  • Question 3/10
    2 / -0.5

    Find the proportion equivalent to M : N : O : P if M : N = 8 : 15, N : O = 5 : 9 and O : P = 18 : 19 ?

    Solutions

    Shortcut Trick

    Traditional Method:

    Given:

    M : N = 8 : 15

    N : O = 5 : 9

    O : P = 18 : 19

    Calculation:

    N : O = 5 : 9 

    We multiply the above ratio by 2, we get

    N : O = 10 : 18

    And we have O : P = 18 :19

    So, N : O : P = 10 : 18 : 19 

    M : N = 8 : 15

    We multiply this by 2

    ⇒ M : N = 16 : 30

    And N : O : P = 10 : 18 : 19 

    We multiply this by 3

    ⇒ N : O : P = 30 : 54 : 57

    Now, we get

    M : N : O : P = 16 : 30 : 54 : 57 

    ∴ The equivalent proportional of M : N : O : P is 16: 30 : 54 : 57

  • Question 4/10
    2 / -0.5

    100 men can make 60 chairs in 4 days working 2 hours a day. How many men are required to make 120 chairs in 10 days working 4 hours a day?

    Solutions

    Given:

    Number of days taken by 100 men to make 60 chairs working 2 hours a day = 4 days

    Chairs to be made in 10 days working 4 hours a day = 120

    Formula used:

    (M1 × D1 × H1)/W1 = (M2 × D2 × H2)/W2

    Where, M1, M2 = Number of men D1, D2 = Number of days, H1, H2 = Number of hours, W1, W2 = Work Done

    We will use only the terms that are given in the question

    Calculation:

    According to the question,

    M1 = 100, D1 = 4 days, H= 2 hours and W1 = 60 chairs

    D2 = 10 days, H2 = 4 hours and W2 = 120 chairs

    (M× D1 × H1)/W1 = (M2 × D2 × H2)/W2         

    ⇒ (100 × 4 × 2)/60 = (M× 10 × 4)/120

    ⇒ 100 × 8 × 120 = M× 40 × 60

    ⇒ M2 = 40

    ∴ 40 men are required to make 120 chairs in 10 days working 4 hours a day.

  • Question 5/10
    2 / -0.5

    One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 min, then the slower pipe alone will be able to fill the tank in?

    Solutions

    Shortcut Trick

    Efficiency ratio = 3 : 1

    Total efficiency = 4

    Work done = 4 × 36 = 144 min

    Time taken by slower pipe = 144/1 = 144 min

    ∴ Time taken to fill the tank by the slower pipe is 144 min.

    Traditional method:

    Let the time taken by pipe A to fill the tank be x min

    ⇒ Time taken by pipe B to fill the tank will be x/3 min

    ⇒ Part of tank filled by pipe A in 1 min = 1/x

    ⇒ Part of tank filled by pipe B in 1 min = 3/x

    ⇒ Part of tank filled by pipe A and B together in 1 min = (1/x + 3/x) = 4/x       ----(1)

    Also, given that A and B together can fill the tank in 36 min

    So, part of tank filled by A and B together in 1 min = 1/36      ----(2)

    So, from equation 1 and 2

    ⇒ 4/x = 1/36

    ⇒ x = 144 min

    ∴ Time taken to fill the tank by the slower pipe is 144 min.

  • Question 6/10
    2 / -0.5

    The average weight of 20 boys was marked as 89.4 kg. Later it was found that instead of 87 kg, a value has been marked as 78 kg. Find the correct average weight.

    Solutions

    Given:

    The average weight of 20 boys was marked as 89.4 kg.

    Later it was found that instead of 87 kg, a value has been marked as 78 kg.

    Concept used:

    Total = Mean (Average) × number of entities

    Calculation:

    Total weight of 20 boys = 20 × 89.4 = 1788 kg

    Correct total weight = 1788 - 78 + 87 = 1797 kg

    Hence, the correct average weight = 1797 ÷ 20 = 89.85 kg

    ∴ The correct average weight is 89.85 kg.

  • Question 7/10
    2 / -0.5

    The diameter of a metallic sphere is 6 cm. The sphere is melted and drawn into a wire of uniform circular cross-section. If the length of the wire is 36 m, then what is its radius equal to?

    Solutions

    Given:

    Diameter of sphere = 6 cm

    Radius of sphere = 3 cm

    Length of wire, H = 36m = 3600 cm

    Formula:

    Volume of cylinder = πr2H

    Calculation:

    Let radius of wire be R cm

    According to question,

    Volume of sphere = Volume of Cylinder

  • Question 8/10
    2 / -0.5

    Points D, E and F are on the sides AB, BC and AC, respectively, of triangle ABC such that AE, BF and CD bisect ∠A, ∠B and ∠C, respectively. If AB = 6 cm, BC = 7 cm and AC = 8 cm, then what will be the length of BE?

    Solutions

    Given

    AB = 6 cm, BC = 7 cm and AC = 8 cm

    Concept

    Internal angle bisector theorem

    The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

    In ∆ABC, AE bisects ∠A.

    (BE/EC) = (AB/AC)

    BE/(7 - BE) = 6/8

    8 BE = 42 - 6BE

    14 BE = 42

    BE = 42/14

    BE = 3 cm

    ∴ The length of BE is 3 cm.

  • Question 9/10
    2 / -0.5

    A person borrows Rs. 12,000 for 2 years at 2% p.a. simple interest. He immediately lends it to another person at 17/4% p.a. for 2 years. Find his gain in the transaction per year.

    Solutions

    Given:

    Principal = Rs. 12,000

    Rate% he borrowed = 2%

    Rate% he lends = 17/4%

    Time = 2 years

    Formula used:

    S.I = (P × R × T)/100

    Where S.I = Simple Interest, P = Principal, R = Rate%, T = Time

    Calculation:

    According to the question:

    Interest he pays;

    S.I = (12,000 × 2 × 2)/100

    ⇒ S.I = 480

    Interest he gets;

    S.I = (12,000 × 17/4 × 2)/100 = 1020

    Now,

    Difference in the transaction = 1020 – 480 = 540

    Gain in 1 year = 540/2 = 270

    ∴ His gain in the transaction per year is Rs. 270

    Shortcut Trick

    Difference in rate = 17/4% - 2% = 9/4%

    Gain = 9/4% of 12000

    ⇒ (9/4 × 12000)/100 = 270

    ∴ His gain in the transaction per year is Rs. 270

  • Question 10/10
    2 / -0.5

    A merchant purchases 15 articles @ Rs. 140 each and another 10 articles @ Rs. 120 each and if he sells each article at Rs. 143, then find the profit percent of the merchant.

    Solutions

    Given 

    A merchant purchases 15 articles @ Rs. 140 each

    A merchant purchases other 10 articles @ Rs. 120 each

    Selling Price of each article = Rs. 143 

    Formula used 

    Profit percent = (Selling price - Cost Price)/Cost Price × 100

    Calculation 

    The total Cost Price = 140 × 15 + 120 × 10 = Rs. 3300 

    The total Selling Price = 143 × 25 = Rs. 3575 

    Profit percentage = (275/3300) × 100 = 8.33% 

    ∴ The required answer is 8.33%

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