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Time, Speed & Distance Test 301
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Time, Speed & Distance Test 301

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  • Question 1/10
    1 / -0.25
    Ram and Suresh are standing on two points 300 m apart from each other. They start running with speeds of 12 km/h and 15 km/h respectively in the same direction. What is distance covered by Suresh to catch Ram?
    Solutions
    speed of ram = 12km/h
    speed of suresh = 15km/h
    Relative speed = (15 – 12) = m/s
    Total distance between them = 300 m
    Required time = = 360 sec
    Distance covered by Suresh = 15 ×  × 360 = 1500 m
  • Question 2/10
    1 / -0.25
    A man covers the journey from a station A to station B at a uniform speed of 36 km/hr and returns to A with a uniform speed of 45 km/hr. His average speed for the whole journey is:
    Solutions
    Here same distances are covered at different speeds.
    Hence, Average speed (if x and y are the speeds) = 

    Therefore, Average speed = 
    = 40 km/hr
  • Question 3/10
    1 / -0.25
    If two trains A and B start at the same time in opposite directions from two stations and arrive at their destinations 4 hours and 9 hours, respectively, after crossing each other, what is the ratio of the speed of train A to that of train B?
    Solutions
    Speed of A /Speed of B =
    Note : In such type of questions when time after the meeting is given instead of total time, this formula is used.
  • Question 4/10
    1 / -0.25
    A man travels 50 km at speed 25 km/h and next 40 km at 20 km/h and there after travel 90 km at 15 km/h. His average speed is
    Solutions
    Time taken by the man to travel 50 km at speed 25 km/h
    Time taken by the man to travel next 20 km at speed 20 km/h
    Time taken by the man to travel next 90 km at speed 15 km/h
    Now, we have,
    Average speed =
  • Question 5/10
    1 / -0.25
    The speed of a train is that of a car. both start simultaneously from New Delhi to Bhopal at the same time. Both reach at Bhopal at same time which is 396 km away from New Delhi. On the way train takes 1hr 50 minutes for stopping at the stations. Find the speed of train.
    Solutions
    Short Trick:
              S         T           D
    Train  4          3          396
    Car    3          4          396
    1 unit difference in time = 1 hr 50 min. = 11/6 hours
    time taken by train = 3 unit = 33/6 = 11/2 hours
    Speed of train = 396*2/11 = 72 Km/hr
    Basic Method:
    Speed of train is 33     that of car

    Let the speed of train be 4x and that of car be 3x 
    Then,

    On solving we get x = 18 
    Required → 4x = 4*18 = 72 km/h.
  • Question 6/10
    1 / -0.25
    A boy is late by 9 min, if he walks to school at a speed of 4 km/h. If he walks at the speed of 5 km/h, he arrives 9 min early. The distance to his school is
    Solutions
    Let the distance between school and his home be x km.
    Then,
    Time taken by the boy to cover a distance of x km at a speed of 4km/hr = hr
    Time taken by the boy to cover a distance of x km at a speed of
    5 km/hr = hr
    According to the question,
     
    Thus, the distance between school and his home 6 km.
    Hence, option D is correct.
  • Question 7/10
    1 / -0.25
    A car travelling at an average speed of 72 km/hr takes 9 minutes to travel a certain distance. By how much should it increase its speed (in km/hr) to travelthe same distance in 8 minutes?
    Solutions
    Distance = speed × time

    New speed

    km/h
    Increased speed km/h.
  • Question 8/10
    1 / -0.25
    Two trains of lengths 70 m and 80 m are running at speeds of 68 km/hr and 40 km/hr respectively on paralleled tracks in opposite directions. in how many second will they pass each other?
    Solutions
    Relative Speed = 68 + 40 = 108 km/hr


    Hence Option C is correct
  • Question 9/10
    1 / -0.25
    A man travelled a distance of 61 km. In 9 hours, partly by walking at speed of 4 km/hr and partly on bicycle at speed of 9 km / hr. The distance covered by walking is
    Solutions
    Total distance travelled by the man = 61 km
    Let the distance covered by walking be x.
    We know that, speed = distance/time

    ⇒ 9x + 244 – 4x = 324
    ⇒ 5x = 80
    ⇒ x = 16 km
  • Question 10/10
    1 / -0.25
    If a person walks at 12 km/hr instead of 10 km/hr, he would have walked 1 km more in the same time. What is the actual distance (in kms) travelled by him at 10 km/hr in the same time?
    Solutions
    Given: If a person walks at 12 km/hr instead of 10 km/hr, he would have walked 1 km more in the same time
    Difference in speed = 12 – 10
    = 2 km/hr
    If the speed is 2 km/hr, distance travelled = 1 km
    ∴ If the speed is 1 km/hr, distance travelled = ½ km
    Thus, if the speed is 10 km/hr, actual distance travelled = 10/2
    = 5 km
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