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IBPS PO 2022 Aptitude Test - 2
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IBPS PO 2022 Aptitude Test - 2

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  • Question 1/10
    1 / -0.25

    Directions For Questions

    Direction: A distributor collects 7 different items from a company.

    The graph given below shows the cost(in Rs.) that he pays for each of the items.

    The graphs given below shows the mark-up and discount percentage on the items.

    ...view full instructions

    On which items is the profit percent the minimum and the maximum?

    Solutions

    CP for coffee = Rs. 200 and mark up % = 25%

    Hence MP = 200 x 1.25 = Rs. 250

    Discount = 8%

    Hence SP = 250 x 0.92 = Rs. 230

    So Profit = Rs. 30 and Profit % = 30/200 x 100 = 15%

    Similarly, calculating for the remaining items, we get:

    The profit percent is the minimum on shampoo and deodorant (5% each), while it is the maximum on toothpaste and soap. (36% each)

     

  • Question 2/10
    1 / -0.25

    Directions For Questions

    Direction: A distributor collects 7 different items from a company.

    The graph given below shows the cost(in Rs.) that he pays for each of the items.

    The graphs given below shows the mark-up and discount percentage on the items.

    ...view full instructions

    The distributor sold 5 packets of coffee, 8 bottles of ketchup and 25 chocolates to a customer. Find his profit percentage in the transaction.

    Solutions

    CP for coffee = Rs. 200 and mark up % = 25%

    Hence MP = 200 x 1.25 = Rs. 250

    Discount = 8%

    Hence SP = 250 x 0.92 = Rs. 230

    So Profit = Rs. 30 and Profit % = 30/200 x 100 = 15%

    Similarly, calculating for the remaining items, we get:

    Total cost of the items = (5 x 200) + (8 x 125) + (25 x 80) = Rs. 4000

    Total selling price = (5 x 230) + (8 x 132) + (25 x 108) = Rs. 4906

    Profit = Rs 906

     

  • Question 3/10
    1 / -0.25

    Directions For Questions

    Direction: A distributor collects 7 different items from a company.

    The graph given below shows the cost(in Rs.) that he pays for each of the items.

    The graphs given below shows the mark-up and discount percentage on the items.

    ...view full instructions

    Certain volumes of coffee and chocolates were sold such that the total discount on coffee equals the total discount on chocolates. What is the profit percent in the transaction?

    Solutions

    CP for coffee = Rs. 200 and mark up % = 25%

    Hence MP = 200 x 1.25 = Rs. 250

    Discount = 8%

    Hence SP = 250 x 0.92 = Rs. 230

    So Profit = Rs. 30 and Profit % = 30/200 x 100 = 15%

    Similarly, calculating for the remaining items, we get:

    Discount offered on one unit of coffee = Rs. 20 and on one unit of chocolate = Rs. 12

    This is in the ratio 5 : 3.

    Since the total discount on each of the items is the same, the ratio of their quantities sold must be 3 : 5

    Suppose, 3 packs of coffee and 5 chocolates were sold.

    Total CP = (200 x 3) + (80 x 5) = Rs. 1000

    Total SP = (230 x 3) + (108 x 5) = Rs. 1230

     

  • Question 4/10
    1 / -0.25

    Directions For Questions

    Direction: A distributor collects 7 different items from a company.

    The graph given below shows the cost(in Rs.) that he pays for each of the items.

    The graphs given below shows the mark-up and discount percentage on the items.

    ...view full instructions

    Toothpaste, soap and shampoo were sold to a customer such that the profit on each category of the items was the same. If the total profit was Rs. 810, what was the cost price of the items?

    Solutions

    CP for coffee = Rs. 200 and mark up % = 25%

    Hence MP = 200 x 1.25 = Rs. 250

    Discount = 8%

    Hence SP = 250 x 0.92 = Rs. 230

    So Profit = Rs. 30 and Profit % = 30/200 x 100 = 15%

    Similarly, calculating for the remaining items, we get:

    Total cost price = (50 x 15) + (25 x 30) + (60 x 90) = 750 + 750 + 5400 = Rs. 6900

     

  • Question 5/10
    1 / -0.25

    Directions For Questions

    Direction: A distributor collects 7 different items from a company.

    The graph given below shows the cost(in Rs.) that he pays for each of the items.

    The graphs given below shows the mark-up and discount percentage on the items.

    ...view full instructions

    The distributor managed the bills using a software. By mistake, he swapped the markup and discount percentages for the products. As a result, the selling prices would yield losses. Which product would give the minimum percent loss in this case?

    Solutions

    CP for coffee = Rs. 200 and mark up % = 25%

    Hence MP = 200 x 1.25 = Rs. 250

    Discount = 8%

    Hence SP = 250 x 0.92 = Rs. 230

    So Profit = Rs. 30 and Profit % = 30/200 x 100 = 15%

    Similarly, calculating for the remaining items, we get:

    On swapping the markup and discount percentages.

    Coffee: Markup = 8%, Discount = 25%

    SP = 1.08 x 0.75 = 0.81 CP

    Loss = 19%

    Similarly, calculating for other products, we get

    Hence the loss percent is the least for ketchup.

     

  • Question 6/10
    1 / -0.25

    What should come in place of the question mark '?' in the following number series?

    17, 66, 102, 127, 143, ?

    Solutions

    17+72=17+49=66

    66+62=66+36=102

    102+52=102+25=127

    127+42=127+16=143

    143+32=143+9=152

     

  • Question 7/10
    1 / -0.25

    What value should come in the place of question mark(?) in the following series?

    111, 258, 391, 510, ?, 706

    Solutions

    The pattern of the series is:

    111     258      391      510     615      706
        +147   +133    +119     +105     +91
                -14     -14       -14         -14

     

  • Question 8/10
    1 / -0.25

    Find the missing number in the given series.

    5, 33, 221, 1097, 3285, ?

    Solutions

    5×9-12=33

    33×7-10=221

    221×5-8=1097

    1097×3-6=3285

    3285×1-4=3281

     

  • Question 9/10
    1 / -0.25

    What should come in place of question mark (?) in the following number series?

    962, 926, 854, 746, 602, ?

    Solutions

    962-36×1=962-36=926

    926-36×2=926-72=854

    854-36×3=854-108=746

    746-36×4=746-144=602

    602-36×5=602-180=422

     

  • Question 10/10
    1 / -0.25

    Find the missing number in the given series.

    4620, 2310, 770, ? , 22, 2

    Solutions

    4620÷2=2310

    2310÷3=770

    770÷5=154

    154÷7=22

    22÷11=2

    (Dividing by the prime numbers)

     

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