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Time & Work Test 229
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Time & Work Test 229

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  • Question 1/10
    1 / -0.25
    A can do a piece of work in 10 days while B can do it in 6 days. B worked at it for 4 days. How long will A take to finish the remaining  work ?
    Solutions

    B’s 4 days work =


    ∴ Remaining work =


    A’s 1 day’s work =


    ∴  work is finished by A in



  • Question 2/10
    1 / -0.25
    3 men can do a piece of work in 18 days. 6 children can also do that work in 18 days. 4 men and 4 children together will finish the work in how many days ?
    Solutions

    3 men = 6 children


    ⇒ 1 man = 2 children


    ∴ 4 men + 4 children



    According to the formula,


    M1D1W2 = M2D2W1


    ⇒ 3 × 18 × 1 = 6 × D2 × 1



  • Question 3/10
    1 / -0.25
    A and B can do a work in 24 and 36 days respectively. They began the work together, but A left after sometime and B finished the remaining work in 11 days. After how many days did A leave.
    Solutions

    Let A and B both work together for x days. And B’s remaining work = 4×11 = 44 unit

    A.T.Q.:
    6x + 4x + 4 × 11 = 144

    ⇒ 10x + 44 = 144

    ⇒ 10x = 144 - 44 = 100

    ⇒ x = 10 days

    Hence, after 10 days A left the work.

  • Question 4/10
    1 / -0.25
    6 men can complete a work in 10 days, 9 women can complete it in 15 days and 15 children can complete the same work in 20 days. In how many days can 10 men, 15 women and 20 children complete the same work?
    Solutions

    1 man’s 1 day work =  =

    1 woman’s 1 day work =  =

    1 children 1 day work =  =

    Work done by 10 men, 15 women and 20 boys

    =

    =

    =  =

    So, required days,

    =  days =  days

  • Question 5/10
    1 / -0.25
    20 men complete one-third of a work in 20 days. How many more men should be employed to finish the rest of work in 25 more days ?
    Solutions

    According to the formula,


    M1D1W2 = M2D2W2




    ⇒ 16 × 2 = 20 + x


    ∴ x = 32 – 20 = 12


  • Question 6/10
    1 / -0.25
    If m men working m hours per day, can do m units of work in m days, then n men working n hours per day would be able to complete how many units of work in n days ?
    Solutions

    Let the required number of units of work = x


    According to the formula


    M1T1D1W2 = M2T2D2W1


    ⇒ m × m × m × x = n × n × n × m



  • Question 7/10
    1 / -0.25
    A and B can do a piece of work in 16 days and 15 days. As they were ill, they could do 80% and 60% of their efficiency respectively. How many days will they take to complete the work together.
    Solutions

    A can complete the work now = 16 ×  = 20 days

    B can complete the work now = 15 ×  = 25 days

    Total one-day work of A and B

    =  +  =  =

    Time taken by them working together

    =  =  days

  • Question 8/10
    1 / -0.25
    If 1 man or 2 women or 3 boys can do a work in 94 days, then in how many days will 3 men, 5 women and 7 boys do the same work.
    Solutions

    1 man = 2 women = 3 boys = 94 days

    1 man = 94 days

    1 man one day work =

    For 3 man =  ---------------- (1)

    2 women = 94 days

    For 5 women =  -------------- (2)

    3 boys = 94 days

    1 boys =

    For 7 boys =  ----------------- (3)

    From eq. (I), (II) and (III) for one work.

    (+  + ) × D = 1

    × D = 94

     × D = 94

    D = 12 days.

  • Question 9/10
    1 / -0.25
    A and B together can do a piece of work in 15 days, while B alone can finish it in 25 days. A alone can finish the work in.
    Solutions

    For, A =  =

    =  days

  • Question 10/10
    1 / -0.25
    There is sufficient food for 116 men for 25 days. After 21 days , 100 men leave the place. For how many days will the rest of the food last for the rest of the men?
    Solutions

    116 x 25 = (116 x 21) + 16 x n
    116 x 4 = 16 x n
    n = 29 days

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