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If θ is acute angle and cos2 θ − sin2 θ = −1/2; then the value of [cos2 2θ + cot2 (θ/2)] is:
An article is sold at a profit of 32%. If the cost price is increased by 20% and the sale price remains the same, then the profit percentage becomes:
Let the CP = Rs. 100 then SP = Rs. 132
Now, CP = Rs. 120 and SP = Rs. 132
Ram can complete a certain work in 35 days and Shyam can complete the same work in 15 days. They worked together for 7 days, and then Shyam left the work. In how many days Ram can complete the 3/7th part of the remaining work.
Let the total work be 105x.
If x = 16, then find the value of x6 – 17x5 + 17x4 – 17x3 + 17x2 – 17x – 1:
Given, x6 – 17x5 + 17x4 – 17x3 + 17x2 – 17x – 1
= x6 – (16 + 1)x5 + (16 + 1)x4 – (16 + 1)x3 + (16 + 1)x2 – (16 + 1)x – 1
= x6 – (x + 1)x5 + (x + 1)x4 – (x + 1)x3 + (x + 1)x2 – (x + 1)x – 1
= x6 – x6 – x5 + x5 + x4 – x4 – x3 + x3 + x2 – x2 – x – 1
= –x – 1
= –16 – 1
= –17
Directions For Questions
Direction: In the following table the number of unit manufacture and sold by five companies - P, Q, R, S, and T has been given. study the given data carefully and answer the question.
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What is the respective ratio between the number of units sold by company S and that sold by company Q ?
⇒Number of units sold by company S = 35
⇒Number of unit sold by company Q = 40
⇒Required ratio = 35 /40 = 7 / 8 or 7 : 8
which company sold highest percentage of units as compared to manufactured by it ?
percentage sale of
⇒Company P = 30 / 45 × 100 = 66.67
⇒Company Q = 40 / 55 × 100 = 72.72
⇒Company R = 45 / 60 × 100 = 75
⇒Company S = 35 / 40 × 100 = 87.5
⇒Company T = 55 / 70 × 100 = 78.57
∴ the highest percentage of units as compared to manufactured is sold by company S.
Direction: Percentage distribution of student and girls in a college studying in various discipline are given below. Study the following Pie chart carefully answer the given question.
The number of girls in commerce is approximately what percent of total number of student in commerce?
If the sides of a triangle are 119 cm, 120 cm and 169 cm then find the radius of circle, circumscribing the triangle.
As given:
The average of 19 results is 122. If the average of first 10 results is 92 and that of the last 10 results is 149, then what will be the 10 result?
Here, Total marks = 19 × 122 = 2318
Marks of First 10 results = 10 × 92 = 920
Marks of Last 10 results = 10 × 149 = 1490
So, marks of 10th result = 1490 + 920 − 2318 = 92
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