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CDS II 2021 Mathematics Test - 13
Result
CDS II 2021 Mathematics Test - 13

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  • Question 1/10
    1 / -0.33

    Solutions

     

  • Question 2/10
    1 / -0.33

    Solutions

     

  • Question 3/10
    1 / -0.33

    A, B and C together can complete a work in  days. A can complete the work in 6 days and B can do the same work in 18 days. In how many days, C alone can complete the same work?

    Solutions

    A, B and C together can complete a work in  days.

    A can complete the work in 6 days.

    B can do the same work in 18 days.

     

  • Question 4/10
    1 / -0.33

    Solutions

     

  • Question 5/10
    1 / -0.33

    A pole is standing erect on the ground which is horizontal. The tip of the pole is tied tight with a rope of length √12 m to a point on the ground. If the rope is making 30 ° with the horizontal, then the height of the pole is

    Solutions

     

  • Question 6/10
    1 / -0.33

    Solutions

    We have,

     

  • Question 7/10
    1 / -0.33

    A 61 digit number is formed by writing the first x natural numbers in front of each other as 12345678910111213… Find the remainder when this number is divided by 8.

    Solutions

    We know that When we divide a number (greater than three digits) by 8 , we can obtain remainder simply by dividing last three digit of that number.

    Now, total digits = 61

    One digit natural number = 9

    Remaining digits = 61 – 9 = 52

    After that we will write two digit natural number.

    Now, 26 × 2 = 52

    So, we can understand that we have to write 26 two-digit natural number(10-35).

    Now, Last three digits of the resultant number = 435

    When, we divide 435 by 8, we obtain 3 as a remainder.

    So, Required remainder = 3

     

  • Question 8/10
    1 / -0.33

    Solutions

    Note- Let  is a quadratic equation. If a is positive and D< 0 then value of quadratic equation for real values of x will always be positive.

     

  • Question 9/10
    1 / -0.33

    A man loses 20% of his money. After spending 25% of the remainder, he has Rs. 480 left. What is the amount of money he originally had?

    Solutions

    Original money = (480 ×100×100)/(100-20)(100-25) = Rs. 800

     

  • Question 10/10
    1 / -0.33

    Solutions

     

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