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SUPER 20 Quant Test 219
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SUPER 20 Quant Test 219

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  • Question 1/20
    1 / -0.25

    Directions For Questions

    Direction: What approximate value should come in place of question mark (?) in following questions?

    ...view full instructions

    Solutions

    Approximating the values:

    ? =

      = (13 − 5) × (14 + 2) 

      = 8 × 16
     
      = 128

  • Question 2/20
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    Directions For Questions

    Direction: What value should come in place of (?) in the following question?(You do not have to calculate the exact value)

    ...view full instructions

    × 1299.982 = ?
    Solutions
    ? = √1521÷×1300
    ? = 39÷(×1300)
    ? = 39×
    ? = 0.04
  • Question 3/20
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    Directions For Questions

    Direction: Find the wrong term in the given series:

    ...view full instructions

    80, 129, 193, 293, 465, 751
    Solutions

    The Pattern of the series is:-

    Pattern is such that squares of number is added. Also these numbers are increasing in the order like:

    Thus, the incorrect number is 465.

    So option (d) is the correct answer.

  • Question 4/20
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    Directions For Questions

    Direction: Find the wrong term in the given series:

    ...view full instructions

    37, 48, 81, 138, 213, 312
    Solutions

    The Pattern of the series is:-

    37 + 11 × 1 = 48

    48 + 11 × 3 = 81

    81 + 11 × 5 = 136

    136 + 11 × 7 = 213

    213 + 11 × 9 = 312

    So option (c) is the correct answer.

  • Question 5/20
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    Directions For Questions

    Direction: In the following question two equations are given in variables X and Y. You have to solve these equations and determine the relation between X and Y.

    ...view full instructions

    I. X2 - 112X + 327 = 0

    II. Y2- 5Y + 6 = 0

    Solutions

    X2 -112 X +327 = 0

    ⇒ X2 - 109X -3X + 327 = 0

    ⇒ X(X -109) -3(X - 109) = 0

    ⇒ (X -3)(X - 109) = 0

    X = 109, 3

    (ii) Y2 -5 Y+6 = 0

    ⇒ Y2 - 3Y - 2Y +6= 0

    ⇒ Y(Y - 3) - 2(Y - 3) = 0

    ⇒ (Y - 3)(Y - 2) = 0

    Y = 2, 3

    Hence, X ≥ Y

  • Question 6/20
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    Directions For Questions

    Direction: In the following question two equations are given in variables X and Y. You have to solve these equations and determine relation between X and Y.

    ...view full instructions

    I.

    II. 15y2 - 20y - 275 = 0

    Solutions

    I.

    II. 15y2 - 20y - 275 = 0

    15y2 - 75y + 55y - 275 = 0

    Hence, option B is correct.

  • Question 7/20
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    Directions For Questions

    Direction: What value should come in place of the question mark (?) in the following question?

    ...view full instructions

    637.28 – 781.47 + 257.39 = ?
    Solutions
    637.28 – 781.47 + 257.39 = ?
    ⇒ ? = 894.67 – 781.47 = 113.2
  • Question 8/20
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    Directions For Questions

    Direction: What value should come in place of the question mark (?) in the following question?

    ...view full instructions

    98 × 64 − 3504 = ?
    Solutions
    98 × 64 − 3504 =?
    6272-3504=?
    2768=?
    Hence, Option B is correct.
  • Question 9/20
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    Directions For Questions

    Direction: What should come in place of the question mark (?) in the following number series?

    ...view full instructions

    625 , 746 , 915 , 1140 , 1429 , ?
    Solutions

    625 , 746 , 915 , 1140 , 1429 , 1790

    Hence, option B is correct.

  • Question 10/20
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    Directions For Questions

    Direction: What should come in place of the question mark '?' in the following number series?

    ...view full instructions

    14, 15, 16, 18, 24, 48, 168, ?
    Solutions

    Pattern of the series is:

    14 + 0! = 15

    15 + 1! = 16

    16 + 2! = 18

    18 + 3! = 24

    24 + 4! = 48

    48 + 5! = 168

    168 + 6! = 888

  • Question 11/20
    1 / -0.25

    Directions For Questions

    Direction: Study the Pie chart and answer the questions.

    Below Pie chart shows the percentage distribution of population of 5 different villages in 2000.

    Total population in 2000 = 5000

    ...view full instructions

    Total population of village P and village S together is how much percent more or less than the total population of village Q and village T together?

    Solutions

    Total population of village P and village S together = 33% of 5000

    = 33 × 50 = 1650

    Total population of village Q and village T together = 40% of 5000

    = 40 × 50 = 2000

    Required percent = () × 100% = 17.5% less

  • Question 12/20
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    Directions For Questions

    Direction: Study the Pie chart and answer the questions.

    Below Pie chart shows the percentage distribution of population of 5 different villages in 2000.

    Total population in 2000 = 5000

    ...view full instructions

    If the ratio of population of village R and village W is 5 : 11, then find the total population of village W.
    Solutions

    Total population of village R = 27% of 5000 = 1350

    Also, given

     =

    Total population of village W = 1350 ×  = 2970

  • Question 13/20
    1 / -0.25

    Directions For Questions

    Direction: Study the Pie chart and answer the questions.

    Below Pie chart shows the percentage distribution of population of 5 different villages in 2000.

    Total population in 2000 = 5000

    ...view full instructions

    What is the central angle of population of villages R and S together?
    Solutions

    We know that

    100% = 360°

    1% = 3.6

    Then,

    Central angle of population of village R and village S = 45% = 45 × 3.6° = 162°

  • Question 14/20
    1 / -0.25

    Directions For Questions

    Direction: Study the Pie chart and answer the questions.

    Below Pie chart shows the percentage distribution of population of 5 different villages in 2000.

    Total population in 2000 = 5000

    ...view full instructions

    If the population of village V is % less than population of village T and out of which male to female ratio is 4 : 1, then find the difference between male population and female population of village V.
    Solutions

    Total population of village T = 21% of 5000 = 1050

    Total population of village V = 1050 × (1 − ) = 1050 ×  = 900

    Total male population of village V = 900 ×  = 720

    Total female population of village V = 900 – 720 = 180

    Required difference = 720 – 180 = 540

  • Question 15/20
    1 / -0.25

    Directions For Questions

    Direction: Study the Pie chart and answer the questions.

    Below Pie chart shows the percentage distribution of population of 5 different villages in 2000.

    Total population in 2000 = 5000

    ...view full instructions

    What is the difference of population of villages P and Q together and village S and T together?
    Solutions

    Total population of villages P and Q together = 34% of 5000

    = 34 × 50 = 1700

    Total population of villages S and T together = 39% of 5000

    = 39 × 50 = 1950

    Difference = 1950 − 1700 = 250

  • Question 16/20
    1 / -0.25
    Arpit has a garden in the shape of a circle. He cuts a square field of the maximum possible area from his garden. Find the area of that square field if the cost of fencing the circular garden at Rs. 7.5 per meter is Rs. 660.
    Solutions
    Let side of square be A m and radius of garden be R m.

    Perimeter of circular garden =

    Radius of circular garden =

    Diagonal of square =  = diameter of garden = 2 × 14 = 28 m

    ⇒ A =  m

    Area of square = (A)² = ² = 392 m²

  • Question 17/20
    1 / -0.25
    Reshmi and Sulogna invested in a project Rs. 1800 and Rs. 2500. After 4 months, Sulgona again invested Rs. 2000 and Reshmi took back whole amount after 5 months. Moutrisha invested Rs. 3500, 5 months before the year ends. According to the agreement, Reshmi will get 3% of the total profit for maintenance of the project. The total profit amount is Rs. 29000 at the end of the year. How much amount Reshmi will get?
    Solutions
    Reshmi and Sulogna invested in a project Rs. 1800 and Rs. 2500. After 4 months, Sulgona again invested Rs. 2000 and Reshmi took back whole amount after 5 months. And, Moutrisha invested Rs. 3500, 5 months before the year ends.
    Equivalent capital of Reshmi
    = Rs. (1800 × 5)
    = Rs. 9000
    So, equivalent capital of Sulogna
    = Rs. (2500 × 4) + (4500 × 8)
    = Rs. 10000 + 36000
    = Rs. 46000
    And, equivalent capital Moutrisha
    = Rs. (3500 × 5)
    = Rs. 17500
    So, the ratio of their shares
    = 9000 : 46000 : 17500
    = 18 : 92 : 35
    Total profit after one year = Rs. 29000
    Reshmi will get 3% of the total profit for maintenance of the project.
    ∴ Reshmi will get = Rs. 29000 × (3/100) = Rs. 870
    Remaining profit is divided as per the ratio of investment
    Remaining profit= 29000-870=28130
    Share of Reshmi = Rs. 28130 × (18/145) = Rs. 3492
    ∴ The total share of Reshmi = Rs. (870 + 3492) = Rs. 4362
  • Question 18/20
    1 / -0.25
    The sum of the ages of A, B, and C is 54 years. The ratio of the ages of A and C is 1:2. B’s father age is twice the age of B. Sum of the ages of A and C is equal to B’s father age. Calculate the age of B.
    Solutions
    The ratio of the ages of A and C is 1:2.
    Let the age of A = x     and age of C = 2x

    Sum of the ages of A and C is equal to B’s father age.
    Hence, B’s father age = (x+2x) = 3x

    B’s father age is twice the age of B.
    Then B’s age = (1/2)*3x = 1.5x

    The sum of the ages of A, B, and C is 54 years.
    x + 2x + 1.5x = 54
    4.5x = 54
    x = 12

    Hence,
    B’s age = 1.5*12 = 18 years
  • Question 19/20
    1 / -0.25
    Rohit and Deepak together have Rs. 1800. Rohit’s (5/18)th amount is 50 more than Deepak’s (5/9)th amount. Find the ratio of amount Rohit has to amount Deepak has.
    Solutions

    Let amount on Rohit has be Rs. x

    Amount on Deepak has = Rs. (1800 – x)

    So = + 50

    ⇒  = (

    ⇒ 5x = 18900 – 10x

    ⇒ 15x = 18900

    ⇒ x = 1260

    Required ratio = 1260 : (1800 – 1260) = 1260 : 540 = 7:3

    Therefore, option d is correct.

  • Question 20/20
    1 / -0.25
    A grocery seller marks the price of oats 62% above the cost price and gives 15% discount on oats but he cheats customer by giving 8% less in weight. What is his overall profit percentage?
    Solutions
    Let the cost price of 100 gm of oats be INR 100
    He marks the price 62% above the C.P
    ⇒ Marked up price of 100 gm of oats = 162% of 100
    ⇒ Marked up price of 100 gm of oats = INR 162
    He gives a discount of 15% on 100 gm of oats
    ⇒ Discount on 100gm = 15% of 162
    ⇒ Discount on 100 gm = INR 24.3
    ∴Selling price of 100 gm of oats = INR 137.7
    While selling he cheats customer by giving 8% less in weight.
    ⇒ He sold 92 gm instead of 100gm
    ∴Required profit = 
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