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Thermodynamics Test 4
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Thermodynamics Test 4
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  • Question 1/10
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    In a Steady flow process,
    Solutions

    Explanation:

    Steady flow process is a process where: the fluid properties can change from point to point in the control volume but remains the same at any fixed point during the whole process. A steady-flow process is characterized by the following:

    • No properties within the control volume change with time. That is mcv = constant; Ecv = constant
    • No properties change at the boundaries with time. Thus, the fluid properties at an inlet or exit will remain the same during the whole process.
    • The heat and work interactions between a steady-flow system and its surroundings do not change with time.
  • Question 2/10
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    The volume flow rate at the outlet of an air compressor is _______ that at the inlet, even though the mass flow rate of air through the compressor is constant.
    Solutions

    Concept:

    Air compressor:

    An air compressor is a device in which work is done on the air to raise its pressure with an appreciable increase in its density.

    i.e ρ2 > ρ1

    Volume flow rate  (Q˙)

    It is defined as the quantity of fluid (m3) flowing per second through a section. It is given by –

    Q˙=A×V

    where A = area of cross-section and V = velocity at that section.

    Conservation of Mass:

    For a flowing fluid, the quantity of fluid (kg) per second is constant which is given by-

    m˙=ρ1A1V1=ρ2A2V2

    m˙=ρ1Q1=ρ2Q2

    Q2Q1=ρ1ρ2

    ∵ ρ2 > ρ1, ∴ Q2 < Q1 i.e. volume flow rate at the outlet decreases in case of a compressor.

  • Question 3/10
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    Heat and work are examples of

    Solutions

    Explanation:

    Energy interaction for a closed system with its surrounding can take place in two ways: (i) by work transfer (ii) by heat transfer

    Work and heat are modes of energy transfer.

    Heat is energy transferred due to temperature differences only.

    Work is the energy transfer associated with a force acting through a distance.

    Relationship between heat and work:

    • Both are recognized at the boundaries of a system as they cross the boundaries; That is, both heat and water are boundary phenomena
    • Systems possess energy, but not heat or work
    • Both are associated with a process, not a state; Unlike properties, heat or work has no meaning at a state
    • Heat and work, both are path functions; Their magnitude depends on the path followed during a process as well as the end state
  • Question 4/10
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    A steadily flowing ideal gas undergoes adiabatic throttling where T1 is temperature before throttling and T2 is temperature after throttling. Assuming no change in kinetic and potential energy due to throttling, which of the following is correct?
    Solutions

    Explanation:

    Steady flow energy equation:

    h1+v122+z1g+Q=h2+v22+z2g+w

    According to given condition:

    Q = 0, v1 = v2, z1 = z2

    And for throttling process: W = 0

    h1 = h2

    Since the enthalpy of an ideal gas is a function of temperature alone

    T1 = T2 (For ideal gas)

    The enthalpy of a real gas is not a function of temperature alone

    T1 ≠ T2 (For real gas)
  • Question 5/10
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    A small steam whistle (perfectly insulated and doing no shaft work) causes an enthalpy drop of 1.25 kJ/kg. The kinetic energy of the steam at entry is negligible, the velocity of steam at exit is
    Solutions

    Concept:

    The steady flow energy equation is written below:

    h1+V122+Z1g+dQdm=h2+V222+Z2g+dWdm

    where enthalpy, heat and work are in J/kg.

    Calculation:

    Given: 

    δQ = 0, δW = 0, Z1 = Z2, (h1 - h2) = 1.25 kJ/kg = 1.25 × 1000 J/kg

    h1+V122=h2+V222

    K.E1 =0 ⇒ V1 = 0

    (h1h2)=V222

    V2=2(h1h2)=2×1000×1.25=50m/s

  • Question 6/10
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    In a multistage compressor, intercooling is done to
    Solutions

    Explanation:

    Multistage compression:

    An increase in pressure ratio in a single stage reciprocating compressor causes an increase in temperature, a decrease in volumetric efficiency, and an increase in work input.

    So for the same higher pressure ratio, multistage compression is efficient.

    Intercooling

    • In multistage compression with intercooling, where the gas is compressed in stages and cooled between each stage by passing it through a heat exchanger called an intercooler. 
    • Ideally, the cooling process takes place at constant pressure, and the gas is cooled to the initial temperature T1 at each intercooler.
    • Multistage compression with intercooling is especially attractive when gas is to be compressed to very high pressures.
    • P-V and T-S diagram of the compression with intercooling is shown in the figure below:

    • It can be seen that intercooling is done at constant pressure and is represented by a horizontal line on the P-V diagram. 
    • If an intercooler is installed between cylinders, in which the compressed air is cooled between cylinders, then the final delivery temperature is reduced.
    • This reduction in temperature means a reduction in internal energy of the delivered air, and since this energy must have come from the input energy required to drive the machine, this results in a decrease in input work requirement for a given mass of delivered air.
    • By multi staging, the pressure ratio of each stage is lowered. Thus, the air leakage past the piston in the cylinder is also reduced.
    • The low-pressure ratio in a cylinder improves volumetric efficiency.
  • Question 7/10
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    The fraction of heat input that is converted to net-work output is a measure of performance of engine and is called as:

    Solutions

    Explanation:

    Heat engine and its thermal efficiency:

    Work (W) is high-grade energy that can be converted into heat (Q) as low-grade energy completely, but converting heat, a low-grade energy (Q) into work, high-grade energy (W) requires special devices which are known as heat engine.

    The function of a heat engine is to produce work (Wnet) continuously at the expense of heat input (Q1) to it.

    The fraction of heat input (Q1) that is converted to net-work output (Wnet) is a measure of performance of a heat engine and is called thermal efficiency.

    Q1 is the heat taken from the source (TH) and Q2 is the heat transferred to the sink (TL).

    Net-work done by the engine, Wnet = Q1 - Q2.

    Thermal efficiency of heat engine:

    ηthermal=work outputheat input=WQ1Q1Q2Q1=1Q2Q1

    Mechanical efficiency

    The ratio of brake power and indicated power is known as mechanical efficiency.

    ηmech=BPIP

  • Question 8/10
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    The work done equals pdv for
    Solutions

    Concept:

    The non-flow work done by the system (only on the quasi-static process) is given by:

    Wnonflow=12pdV

    Work done in a flow process (any process):

    Wflowprocess=12VdP

  • Question 9/10
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    Work is considered to be a superior form of energy as compared to heat energy, because,

    Solutions

    Explanation:

    • Based on the thermodynamic concepts, an energy source can be called as high - grade or low - grade, depending on the ease with which it can be converted into other forms.
    • Thus electrical energy (or work) is called a high - grade energy, as it is very easy to convert almost all of it into other energy forms such as thermal energy (say by using an electrical heater).
    • Whereas, it is not possible to convert thermal energy (or heat) completely into electrical energy (typical efficiencies of thermal power plants are around 30 percent), hence thermal energy is called a low - grade energy. 
  • Question 10/10
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    Heat and work are
    Solutions

    Explanation:

    Heat and work, both are path functions; Their magnitude depends on the path followed during a process as well as the end state.

    • Work and heat are modes of energy transfer.
    • Heat is energy transferred due to temperature differences only.
    • Work is the energy transfer associated with a force acting through a distance.

    Relationship between heat and work:

    • Both are recognized at the boundaries of a system as they cross the boundaries; That is, both heat and work are boundary phenomena
    • Systems possess energy, but not heat or work
    • Both are associated with a process, not a state; Unlike properties, heat or work has no meaning at a state

    Property

    Work & Heat

    It is a state or point function

    They are path functions

    They are independent of path history

    They are dependent on path history

    They are exact differential

    They are inexact differential

    Properties are classified into two types.

    • Intensive property: The properties of the system which are independent of the mass of a system are called Intensive property.
      • E.g. pressure, density, temperature, all specific properties, etc.
    • Extensive property: The properties of the system which are dependent on the mass of a system are called Extensive property.
      • E.g. energy, volume, entropy, etc.
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