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IBPS PO 2021 Aptitude Test - 48
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IBPS PO 2021 Aptitude Test - 48

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  • Question 1/10
    1 / -0.25

    Each of the question is followed by two statements I and II. You have to decide which statement is sufficient to answer the question.

    Find the time taken by B to complete the whole work alone.

    Statement I: A is 50% more efficient than B and ratio of efficiency of A and C is 5:4 respectively. Time taken by C to complete the whole work alone is 12 days less than B.

    Statement II: A and B together can complete the whole job in 144/5 days and B takes 24 days more than A to complete the job alone.

    Solutions

    Statement I: Ratio of efficiency of A and B = 3:2

    Ratio of efficiency of A and C = 5:4

    Ratio of efficiency of A: B: C = 15:10:12

    Ratio of time = 4:6:5

    According to question

    (6 – 5) unit = 12

    1 unit = 12

    Time taken by B = 12 x 6 = 72 days

    This statement alone is sufficient to answer the question

    Statement II. Let the time taken by A to complete the job = a days

    Time taken by B = a + 24

    According to question,

    1/a + 1/ (a + 24) = 5/144

    On putting a + 24 = 72

    a = 48

    So, 1/48 + 1/72 = 5/144

    This value satisfying the option.

    This statement alone is sufficient to answer the question.

     

  • Question 2/10
    1 / -0.25

    Each of the question is followed by two statements I and II. You have to decide which statement is sufficient to answer the question.

    If Length of Train Y is 20% more than length of train X. Find the length of train X.

    Statement I: Train Z is running at speed of 70 m/s. If train Y and Z are running in same direction then train Z can cross train Y in 35 seconds.

    Statement II: Train X running at 40 m/ s, crosses a man standing in bridge in 6.25 seconds. Train Y running at 60 m/s, crosses same man in 5 seconds.

    Solutions

    Statement I. This is clear from the statement that we can’t calculate length of train Y or train Z. So we are not able to calculate the length of train X.

    This statement alone is not sufficient.

    Statement II. Let the length of train X = 5a

    Length of train Y = 1.2 x 5a = 6a

    According to statement,

    5a = 40 x 6.25 = 250

    a = 50 meters

    Length of train X = 50 x 5 = 250 meters

    This statement alone is sufficient to answer the question

     

  • Question 3/10
    1 / -0.25

    Each of the question is followed by two statements I and II. You have to decide which statement is sufficient to answer the question.

    Ranjan bought an article from shopkeeper, find the cost price of article for shopkeeper.

    Statement I: The ratio of marked price and cost price of article is 4:5 and discount is Rs. 750

    Statement II: The marked price of article is Rs. 9000

    Solutions

    This is very clear that both statements alone are not sufficient to answer the question.

    On combining both statements

    5a = 9000

    a = 1800

    Cost price of article = 4 x 1800 = Rs. 7200

     

  • Question 4/10
    1 / -0.25

    Aprajita spends 22% of monthly income on house rent, 14% of remaining income on education, 20% and 5% of remaining on Stock market and monthly EMI for Insurance Policy, he left with Rs. 20,124. Find the total income of Aprajita.

    Solutions

    Let the total income of Aprajita = 100a

    Amount spend on house rent = 22% of 100a = 22a

    Amount spend on education = 14% (100a – 22a) = 14% of 78a = 10.92a

    Amount spend on stock market = 20% (78a – 10.92a) = 20% of 67.08 = 13.416a

    Amount spend on monthly EMI = 5% of 67.08a = 3.354a

    Amount left after all expenditures = 78a – (10.92a+13.416a + 3.354a) = 50.31a

    According to question,

    50.31a = 20124

    a = 400

    Total income = 400 x 100 = 40,000

     

  • Question 5/10
    1 / -0.25

    A, B and C started a business with initial investments of Rs. 4200, Rs. 4800 and Rs. 5400 respectively. After two years they made additional investments of Rs. k + 600, Rs. k + 400 and Rs. k + 200 respectively. Find the profit share of B out of total profit of Rs. 6480.

    Solutions

    Ratio of profit = (4200 x 2 + k + 600) :( 4800 x 2 + k + 400) :( 5400 x 2 + k + 200)

    = (9000 + k): (10000 + k): (11000 + k)

    Profit share of B = (10000 + k) / (9000 + k + 10000 + k + 11000 + k)

    = (10000 + k) / (30000 + 3k) = 1/3 of total profit

    Profit share of B = 1/3 x 6480 = Rs. 2160

     

  • Question 6/10
    1 / -0.25

    There are two mixtures A and B contains milk and water in the ratio of 7:4 and 1:2 respectively. If these two mixtures are mixed in the ratio of 6:5, then find the ratio of milk and water in the resultant mixture?

    Solutions

    Quantity of milk present in the mixture A = 7/11

    Quantity of milk present in the mixture B = 1/3

    Therefore

    Remaining are water, i.e 1- (181/363) = 182/363

    Ratio of milk and water in the final mixture

    181 : 182

     

  • Question 7/10
    1 / -0.25

    Average age of father and mother before five years is 29.If the age of the son is added to their parents then average becomes seven less than the Present average age of father and mother. Find the average age of son, daughter father and mother had son age is 2 years younger than his sister?

    Solutions

    Present average age of father and mother = 29+5 =34

    Total age of the father and mother = 34*2 =68

    Let present age of son =x

    It is given that,

    68+x =81

    Therefore present age of son = 13 years

    Age of daughter = 13+2 = 15 years

    Total average age of the family,

    = (68+13+15)/4

    = 24 years

     

  • Question 8/10
    1 / -0.25

    Person X start from point A and person Y start from point B running towards each and meets first time after 8 hours. (Both start running at same time). Find speed of Y in km/h if speed of X is 200% more than Y and distance between A and B is 960 km.

    Solutions

    Let speed of Y = a km/h

    Speed of X = 300% of a = 3a

    According to question

    960/8 = (3a + a)

    4a = 120

    a = 30

    Speed of Y = 30 km/h

     

  • Question 9/10
    1 / -0.25

    There are 10 boys and 8 girls out of which a team of 8 players to be selected. In how many ways team can be selected if at least 4 girls and 2 boys should be in team?

    Solutions

    Required number of ways = 8C6 x 10C2 +8C5 x 10C3+ 8C4 x 10C4

    = 45 x 28 + 120 x 56 + 210 x 70

    = 1260 + 6720 + 14700 = 22680 ways

     

  • Question 10/10
    1 / -0.25

    Henry bought loan from bank at simple interest which worth Rs.16000 at 12% per annum for 2 years, he lends that amount to Gokul in compound interest at 20% for 2 years, find the amount earned as profit by Henry after 2 years?

    Solutions

    Interest amount paid by Henry after 2 years

    = (16000×2×12)/100

    = Rs.3840

    Interest amount paid by Gokul to Henry after 2 years

    = 16000(1+[20/100])2-16000

    = 16000(36/25) – 16000

    = 23040 – 16000

    = Rs.7040

    Profit amount earned by Henry after 2 years = 7040 – 3840 = Rs.3200

     

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