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CDS Inequalities Test 330
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CDS Inequalities Test 330

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  • Question 1/5
    1 / -0
    For what value of the value of the expression is not positive.
    Solutions
    Alternate: Let Graph of the function crosses x-axis at and . In between -2 and 3 the value of the expression is either +ve or -ve. Let x = 1

  • Question 2/5
    1 / -0
    Which of the point and lie in the solution of the system of inequations and ?
    Solutions
    and
    Putting point P,Q and R in above 2 equations
    P(5,-1)

    True

    True
    Q(3,-2)

    True

    True
    R(1,1)

    True

    False
    Hence P and Q lie in the solution
  • Question 3/5
    1 / -0
    Solve for t :
    Solutions

    Consider

    Suitable method to solve inequalities is Wavy curve method. Steps to draw wavy curve method is given below

    Step -1 : First plot all the zeros of the function on real line.

    Step 2 : Check the value of function for any real number greater than the right most marked number on the number line.

    Step -3 : From right to left, beginning above the number line (in case of value of function is positive in step (2), otherwise, from below the number line), a wavy curve should be drawn to pass through all the marked points so that when it passes through a simple point, the curve intersects the number line, and, when passing through a double point, the curve remains located on one side of the number line.

    Note : If the exponents of a factor is odd then the point is called a simple point and if the exponent of a factor is even then the point is called a double point

    Step -4 The appropriate intervals are chosen in accordance with the sign of inequality (the function is positive whenever the curve is situated above the number line, it is negative if the curve is found below the number line). Their union represents the solution of inequality.

    Hence,

  • Question 4/5
    1 / -0
    Solve
    Solutions

    We can write two equations in order to maintain the expression positive as follows

  • Question 5/5
    1 / -0
    If satisfy then
    Solutions

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