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IBPS PO 2021 Aptitude Test - 39
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IBPS PO 2021 Aptitude Test - 39
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  • Question 1/10
    1 / -0

    P, Q and R start at the same time in the same direction to run around a circular stadium. P completes a round in 252 seconds, Q in 308 seconds and R in 198 seconds, all starting at the same point. After what time will they again at the starting point?

    Solutions

    LCM of 252, 308 and 198 = 2772

    So, A, B and C will again meet at the starting point in 2772 sec

    = 2772/60 = 46 min 12 sec

     

  • Question 2/10
    1 / -0

    Two men A and B undertake work for Rs. 1521 They can complete it in 18 days and 39 days respectively. They work along with a third man C and complete it in 9 days. Find the share of B.

    Solutions

    Let the Total work = 234 units (because 234 is the L.C.M. of 18 and 39)

    A and B work along with the third man C and complete the work in 9 days.

    Work done by B in 1 day = 234/39= 6 units

    Total amount assigned for the work = Rs. 1521

    B’s share in the amount = 1521/234× 6 × 9

    = Rs. 351

     

  • Question 3/10
    1 / -0

    Yogendra sold a computer for Rs. 17,940 with a discount of 8% and gained 19.6%. If no discount is allowed, then what will be his gain percent?

    Solutions

    Let MP = Rs. X, then

    SP = MP – Discount

    17940 = X – 8% of X

    ⇒ 17940 = 0.92X

     

  • Question 4/10
    1 / -0

    A cistern has three pipes A, B and C connected in the bottom. Pipes A and B can fill the cistern in 12 minutes and 18 minutes respectively while pipe C is an outlet pipe which empties the cistern. If the time taken by pipe A and B to fill the cistern when pipe C is also opened is 20 minutes then find the time taken by pipe C to empty the full cistern?

    Solutions

    Let total work = 180 units 
    A’s one minute work = 15 units
    B’s one minute work = 10 units
    A + B + C one minute work = 9 units
    C’s one minute work = 25 − 9 = 16 units
    Time taken by pipe C to empty the cistern = 180/16 = 45/4 minutes

     

  • Question 5/10
    1 / -0

    What approximate value should come in place of the question mark (?) in the following question (Note: You are not expected to calculate the exact value)?

    7320 ÷ 348 × 12 + 33.0003% of 509.999 + (838 ÷ 14.95) × 17.95 = ?

    Solutions

     

  • Question 6/10
    1 / -0

    What approximate value should come in place of the x in the following questions? (You are expected to do approximations)

    x% of (6750 ÷ 15) – 12.12 × 16.16 = 116.99 – 23.99% of 649.891

    Solutions

    By approximation, we get:
    x% of 450 – 12× 16 = 117 – 24% of 650
    ⇒ x × 4.50 – 192 = 117 – 156
    ⇒ x × 4.50 = 192 – 39
    ⇒ x × 4.50 = 153
    ⇒ x = 153 ÷ 4.5
    ⇒ x = 34

     

  • Question 7/10
    1 / -0

    What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value).

    70.04 × 0.81 × 105.05 × 0.2 + 106.08 × 0.51 − 25 + 29.98 = ?

    Solutions

    By approximation, we get:

    ? = 70 × 0.8 × 105 × 0.2 + 106 × 0.5 − 25 + 30

      = 56 × 21 + 53 − 25 + 30

      = 1176 + 53 − 25 + 30  

      = 1234

     

  • Question 8/10
    1 / -0

    What approximate value should come in place of the question mark(?) in the following questions?

    (Note: you are not expected to calculate the exact value)

    Solutions

    By approximation, we get:

     

  • Question 9/10
    1 / -0

    What approximate value should come in place of the question mark(?) in the following questions?

    49.75% of 749.69 + 45% of 420.02 – ? = 152

    Solutions

     

  • Question 10/10
    1 / -0

    What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)

    36.0452 + 6.912 − 37.162 = ?

    Solutions

    By approximation, we get:

    ? = 362 + 72 − 372

    = 1296 + 49 − 1369

    = −24

     

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