Please wait...

Pipes & Cistern Test 110
Result
Pipes & Cistern Test 110

  • /

    Score

  • -

    Rank
Time Taken: -
  • Question 1/10
    1 / -0
    A cistern can be filled by two supply pipes in 20 minutes and 30 minutes respectively. but a waste pipe can empty it in an hour. Both the supply pipes were opened together to fill the empty cistern, but by mistake the waste pipe was also open. How much later was the waste pipe closed, if the cistern is filled in 14 minutes?
    Solutions
    Let the waste pipe be closed after x minutes.
  • Question 2/10
    1 / -0
    A tap can empty a tank in 30 min. A second tap can empty it in 45 min. If both the taps operate simultaneously, how much time is needed to empty the tank?
    Solutions
    Required time
  • Question 3/10
    1 / -0
    Pipe A can fill a tank in 12 hours and Pipe B can fill the tank in 18 hours. If both the pipes are opened on alternate hours and if pipe B is opened first, then in how much time (in hours) the tank will be full?
    Solutions
    let capacity of tank be 72litre (since it is a multiple of both 12 and 18)

    Then efficiency of pipe A=72/12=6  

    Efficiency of pipe B=72/18=4

    Pipes are opened alternatively and pipe B is opened first,, then the water filled in two hour

    = water filled by pipe A+ water filled by pipe B = 6+4=10 litre

    10 litre in 2 hour

    70 litre=

    Remaining volume =72-70=2

    Now it’s B turn to fill the tank , as it started the fist, so time taken=

    So total time taken=14+1/2=
  • Question 4/10
    1 / -0
    A pipe can fill a tank in x hours and another can empty it in y hours. They can together fill it in
    Solutions
    Accrding to question,

    Required time = hour
  • Question 5/10
    1 / -0
    A pump can fill a tank with water in 2 h. Because of a leak in the tank it was taking h to fill the tank. The leak can drain all the water off the tank in:
    Solutions
    Work done in 1 h by the filling pump
    Work done in 1 h by the leak and the filling pump
    ∴Work done by the leak in 1 h

    Hence, the leak can empty the tank in 14 h.
  • Question 6/10
    1 / -0
    Having the same capacity 9 pipes fill up a swimming pool in 20 minutes. How many pipes of the same capacity are required to fill up the same swimming pool in 18 minutes?
    Solutions
    Given,
    9 pipes can fill up the swimming pool in 20 minutes.
    ∴ Part of swimming pool filled by 1 pipe in 1 minutes = 1/(9 × 20) = 1/180
    Let, ‘x’ pipe can fill up the swimming pool in 18 minutes.
    ∴ (1/180) × x × 18 = 1
    ⇒ x/10 = 1
    ⇒ x = 10
  • Question 7/10
    1 / -0
    Pipes X. Y and Z are connected to a water tank and the rate of flow of water is 44 L/h, 55 L/h and 49 L/h respectively. Pipe X and Y fill the tank while pipe Z empties the tank. If all the three pipes are opened simultaneously, the tank gets completely filled up in 14 h. what is the capacity of the tank?
    Solutions
    X, Y and Z ‘s 1 h filling capacity = 44+55-49 =50L/h 
    X, Y and Z ‘s 14 h filling capacity = 50*14 = 700L
  • Question 8/10
    1 / -0
    A tank can be filled by two taps in 25 and 30 minutes resp. There is leakage in the tank which can empty the tank in 15 minutes. If the taps are turned on at same moment, what part of tank will remain unfilled at end of 120 minutes?
    Solutions
    LCM of 25, 15 and 30 is 150.
    Let the two pipes be A and B and leak be considered as tap C which empties the tank.
    Let total work be 150 units.
    Work done by A in 1 min = 150/25= 6 units
    Work done by B in 1 min= 150/30= 5 units
    Work done by C in 1 min = 150/15= -10 units
    Effective work in 1 min=6+5-10 = 1 unit
    Effective work in 120 minutes = 120 units
    Remaining work=150 – 120 units = 30 units
    Hence (30/150) =1/5th of the tank remains unfilled after 120 minutes
  • Question 9/10
    1 / -0
    Three pipes P,Q and R can fill a tank in 4, 8 and 12 hr respectively. One additional pipe S can empty the tank in 10 hr. Then which of the following combination can fill the tank in the least time?
    Solutions
    This question can be solved by option checking.
    So, from option B:
    P and S opened simultaneously,
    Part of tank filled in 1 hr =
    =
    So, tank will be filled in 20/3 hrs.
    From option C:
    P,R and S opened simultaneously,
    Part of tank filled in 1 hr =
    =
    So, tank will be filled in 30/7 hrs.
    From option D:
    P,Q and S opened simultaneously,
    Part of tank filed in 1 hr =
    =
    So, tank will be filled in 40/11 hr.
    From option A:
    Q can fill the tank in 8 hrs.

    So,
    <<<8
    Therefore option D is correct.
  • Question 10/10
    1 / -0
    A tank has 3 pipes A, B and C. A and B can fill it in 3 hours and 4 hours respectively while C can empty it in 1 hour. If the pipes are opened at 3 p.m., 4p.m & 5 p.m. respectively, then find the time in which whole tank will be empty.
    Solutions
    Quant_Time_work_files\image041.png

    (We take LCM of no. of hours and consider it as total water and divide it by no. of hours and get 1 hour's work)

    According to the question, pipe A is opened 2 hours before pipe C and pipe B is opened 1 hours before pipe C.

    So, water filled at 5.p.m. = (4×2) + (3×1) = 11

    If they work together, then their combined efficiency = (4+3-12) = -5.

    Time taken in emptying 11 unit of water = 11/5

    So, the time by which the tank will get emptied = 5 p.m. + 11/5
    = 5.pm. Quant_Time_work_files\image042.png
    = 7:12 p.m.
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Click on Allow to receive notifications
×
Open Now