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CDS Mean, Median & Mode Test 310
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CDS Mean, Median & Mode Test 310

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  • Question 1/5
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    The median of the data 5,5,5,4,4,4,8,11,12,25,84 is:
    Solutions

    Given data : 5,5,5,4,4,4,8,11,12,25,84

    Arrange the data in ascending order : 4, 4, 4, 5, 5, 5, 8, 11, 12, 25, 84

    Total number of terms = 11

    Hence, Median =  =

    6th observation = 5

  • Question 2/5
    1 / -0
    What is the mean deviation about the mean for the data 1 , 3 ,5 ,7 , 11 , 12 , 13 ,20 ?
    Solutions

    Mean = (

    Here   =

    Hence, mean deviation about mean =

    =

    =

  • Question 3/5
    1 / -0
    The variance of 30 observations is 7 . If each observation is multiplied by 3, then what is the new variance of the resulting observations?
    Solutions

    Let  be the given observations.

    Given variance of 30 observations is 7

    ⇒

    Now to find variance of ,

    Let  denotes the mean of new observation

    Clearly ,

    Now variance of new observation =

    =

    =

  • Question 4/5
    1 / -0
    What is the median of 2, 4, 6, …, 100?
    Solutions

    We have,

    2, 4, 6, …… , 100

    So, here  numbers in this A.P. series.

    We know that

      

      

      

    Since there are 50, an even number of items . Therefore median is the arithmetic mean of  and  observations.

    So, 25th observation =

    & 26th observation =

    Median =

  • Question 5/5
    1 / -0
    The marks of Nine students in ascending order for a test are given below with Median as 44, the value of k is: 23, 30, k, 42, k + 13, 50, 52, 58,68.
    Solutions
    Marks of Nine students in ascending order for a test are : 23, 30, k, 42, k + 13, 50, 52, 58,68.

    Median = 44

    If n is odd , Median =  = 5th term

    Now, 5th term = k+13

    A.T.Q.

    ⇒ k + 13 = 44

    ⇒ k = 31

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