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RRB NTPC Memory Based Test 107
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RRB NTPC Memory Based Test 107

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  • Question 1/10
    1 / -0
    Which answer figure will complete the question figure ?

    Solutions
    After close observation, we find that the option B will complete the pattern when placed in the blank space of question figure as shown below,



    So, the correct answer is option B.
  • Question 2/10
    1 / -0
    If “×” means addition, “+” means division, “-” means multiplication and “÷” means subtraction, then find the value of –

    21 × 6 + 3 – 15 ÷ 2

    Solutions

    After changing the symbols,

    21 + 6 ÷ 3 × 15 – 2 (applying BODMAS)

    => 21 + 2 × 15 – 2

    => 21 + 30 – 2

    => 51 – 2

    => 49

    Hence, option D is the correct answer.

  • Question 3/10
    1 / -0
    In the following question, find the missing number from the given options.

    Solutions

    The lower value is the sum of the upper two values,

    From figure (i) –

    15 + 25 = 40

    From figure (ii) –

    17 + 12 = 29

    Similarly from figure (iii) –

    13 + 19 = ?

    ? = 32

    Hence, the correct answer is option B.

  • Question 4/10
    1 / -0
    The variance of a set of data is 196. Then the standard deviation of the data is
    Solutions
    Variance of the data
    Standard deviation of the data
    Standard deviation is always a positive number
  • Question 5/10
    1 / -0
    The sum of ages of a son and his father is 90 years. Seven years later, the ratio of their ages would be 4 : 9. What was the age of the father 12 years ago?
    Solutions
    Let the age of father be x years and age of son be (90–x) years
    Seven years later, the ages would be (x+7) and (97–x)

    ⇒ (97–x)/(x+7) = 4/9
    ⇒ 873 – 9x = 4x + 28
    ⇒ x = 65 years
    So, present age of father is 65 years.
    Age twelve years ago = 65–12 = 53 years.
  • Question 6/10
    1 / -0
    If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., then the gain of B (in Rs.) in a period of 3 years is
    Solutions
    We need to calculate the profit of B.
    It will be,
    SI on the rate B lends - SI on the rate B gets
    Gain of B=(3500×11.5×3)/100−(3500×10×3)/100
    =157.50
  • Question 7/10
    1 / -0
    Who is known as the main architect of unification of moderates and extremists in Lucknow session?
    Solutions
    • The Lucknow Session 1916 which was presided by Ambica Charan Majumdar) brought the moderates and extremists in Congress on the common platform again after nearly a decade, particularly due to efforts of Annie Besant.
  • Question 8/10
    1 / -0
    In Uttar Pradesh, the highest number of fairs are held in the district ?
    Solutions
    The Uttar Pradesh's composite culture is famous all over India so Festivals of almost all the religions are celebrated in U.P.
    • The largest number of fairs are held in Mathura (86), followed by Kanpur and Hamirpur (79), Jhansi (78), Agra (72), and Fatehpur (70).
    • About 2,250 fairs are held every year in Uttar Pradesh.
  • Question 9/10
    1 / -0
    Gamma rays  are used in _______.
    Solutions
    •Gamma rays are electromagnetic radiation with high energy and high frequency.
    •It is used for treatment of cancerous cell in our body without the use of the surgery.
    •It is used in industries to kill the harmful bacteria, organism like yeast etc.
    •Like x – rays, it is also used to sterilize medical instruments.
    •It is used to detect brain and heart abnormalities.
  • Question 10/10
    1 / -0
    The term ‘radio activity’ was first used by
    Solutions
    Henry Becquerel was first to discover radioactivity but Marie Curie was the first one to coin the term radioactivity.
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