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SBI PO 2020 Aptitude Test - 29
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SBI PO 2020 Aptitude Test - 29

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  • Question 1/10
    1 / -0

    What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value).

    Solutions

    By Approximation, we get:

    11 + 24 ÷ 4 – 2 = ? × 3

    ⇒ 11 + 6 – 2 = ? × 3

    ⇒ 15 = ? × 3

    ⇒ ? = 15/3

    ⇒ ? = 5

     

  • Question 2/10
    1 / -0

    What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value).

    5.99 ÷ 2.01 × 17.03 – 47.96 = √?

    Solutions

    By Approximation, we get:

    6 ÷ 2 × 17 – 48 = √?

    ⇒ 3 × 17 – 48 = √?

    ⇒ 51 – 48 = √?

    ⇒ ? = 9

     

  • Question 3/10
    1 / -0

    What approximate value should come in place of the question mark(?) in the following questions? (Note: you are not expected to calculate the exact value)

    (30330 ÷ 30) ÷ 3 = ?

    Solutions

    ? = (30330 ÷ 30) ÷ 3

     

  • Question 4/10
    1 / -0

    What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)

    174.2 × ? ÷ 87 + 94.1 + 125% of 132.1 = 1359

    Solutions

    By Approximation, we get:
    174 × ? ÷ 87 + 94 + 125% of 132 = 1359
    ⇒ 174 × ?/87 + 94 + 165 = 1359
    ⇒ 2 × ? + 259 = 1359
    ⇒ 2 × ? = 1100
    ⇒ ? = 550

     

  • Question 5/10
    1 / -0

    What approximate value will come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)

    (2398.894 + 451.021 – 325.045) ÷ √626 × (14.95)2 = ?

    Solutions

    By Approximation, we get

    (2399 + 451 – 325) ÷ √625 × 225 = ?
    ⇒ 2525 ÷ 25 × 225 = ?
    ⇒ 101 × 225 = ?
    ⇒ 22725 = ?

     

  • Question 6/10
    1 / -0

    Directions For Questions

    Directions: Study the following Bar Graph carefully and answer the questions that follow.

    The given bar graph shows the speeds of two trains in a journey of 500 km. 

    ...view full instructions

    During the journey, if train A covered some distance of 23.94 km in 27 minutes, how much less time did train B take to cover the same distance in the same distance range?

    Solutions

    When train is running at a speed of 53.2 km/hr, at the same time, train B is running at a speed of 59.5 km/hr

    Time taken by the train B to cover the same distance = hours = 24 min

    Therefore, train B took 27 – 24 = 3 min less to cover the same distance.

     

  • Question 7/10
    1 / -0

    Directions For Questions

    Directions: Study the following Bar Graph carefully and answer the questions that follow.

    The given bar graph shows the speeds of two trains in a journey of 500 km. 

    ...view full instructions

    How much more time did train B take to cover the last 100 kms as compared to train A?

    Solutions

    Therefore, required time difference = 91.68 - 86.46 = 5.22 minutes

     

  • Question 8/10
    1 / -0

    Directions For Questions

    Directions: Study the following Bar Graph carefully and answer the questions that follow.

    The given bar graph shows the speeds of two trains in a journey of 500 km. 

    ...view full instructions

    Find the maximum percentage increase in speed of any of the train between any two consecutive distance range.

    Solutions

    Clearly from the graph, the maximum percentage increase in speed between any two consecutive distance range is for Train A between distance range (80 to 150)km and (150 to 200)km.
    Required Percentage increase:

     

  • Question 9/10
    1 / -0

    Directions For Questions

    Directions: Study the following Bar Graph carefully and answer the questions that follow.

    The given bar graph shows the speeds of two trains in a journey of 500 km. 

    ...view full instructions

    For the first 150 km the average speed of train A is what percent more than that of train B.

    Solutions

     

  • Question 10/10
    1 / -0

    Directions For Questions

    Directions: Study the following Bar Graph carefully and answer the questions that follow.

    The given bar graph shows the speeds of two trains in a journey of 500 km. 

    ...view full instructions

    After completing a journey of 210 km, both the trains crossed each other in 12 sec, moving in opposite directions. If train A is 40 m longer than train B, find the lengths of the trains.

    Solutions

    Let the length of train B be ‘x’ m

    Length of train A = (x + 40)m

    After covering 210 km,

    Speed of train A = 65 km/hr

    Speed of train B = 70 km/hr

    Since, they are moving in opposite directions,

    Their relative speed = 65 + 70 = 135 km/hr = 135 × 5/18 = 37.5 m/sec

    Hence,

    Time taken to cross each other = (sum of their lengths) / (their relative speed)

    Therefore, the length of the trains is 205 m and 245 m

     

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