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A Ship of length 150 m traveling from point A to B downstream passes a Ghat along the river in 10 seconds, while in return it passes the same Ghat in 12.5 seconds. If the rate of current is 9 km/h. Find the length of the Ghat.
Let the speed of boat in still water = x metre/second
Let the length of Ghat = a metre
Length of the ship = 150 m
Speed of current = 9 km/h = 9 × 1000/3600 = 2.5 m/s
Speed of boat in downstream = (x + 2.5) m/s
Speed of boat in upstream = (x – 2.5) m/s
⸫ According to the data in the question, equating distance we get
(x + 2.5) × 10 = (x – 2.5) × 12.5
10x + 25 = 12.5x – 31.25
2.5x = 56.25
x = 22.5 m/s
150 + a = 250
a = 100 m
Hence, the length of the Ghat is 100 m.
A person covers 620 km in 16 hours. He covers some distance by a Scooter at an average speed of 30 km/h and the remaining distance by Train at an average speed of 75 km/hr. Find the distance covered by the person on Scooter ?
Total distance covered by the person = 620 km
Total time taken = 16 hours
Speed of person on scooter = 30 km/h
Speed of man in train = 75 km/h
Let the distance covered by the person by scooter = x km
So, the distance covered by the person by train = (620 – x) km
According to the data in the question, equating time we get
On solving the equation, we get
5x + 1240 – 2x = 2400
3x = 1160
x = 386.67 km
Hence, the distance travelled by the man on scooter is 386.67 km.
A total of Rs 1,25,000 is invested in a business. Investment of A is Rs 10,000 less than that of B and B’s investment is Rs 30,000 more than that of C . If A invested his amount for 12 months and B invested his amount for 9 months and C invested his amount for 16 months, then find the share of B if there is a total profit of Rs. 50,225?
Let the investment of B = x
So, the investment of A = x – 10,000
So, the investment of C = x – 30,000
Total amount invested = 1,25,000
⸫ according to the question:
x – 10,000 + x + x – 30,000 = 1,25,000
3x – 40,000 = 1,25,000
3x = 1,65,000
x = 55,000
B’s investment = 55,000
Time period of B’s investment = 9 months
A’s investment = 55,000 – 10,000 = 45,000
Time period of A’s investment = 12 months
C’s investment = 55,000 – 30,000 = 25,000
Time period of C’s investment = 16 months
Ratio of share in profit of A,B,C = 45,000 × 12 : 55,000 × 9 : 25,000 × 16
108 : 99 : 80
Let the share of A,B,C respectively = 108x , 99x , 80x
⸫ according to the question :
108x + 99x + 8x = 50,225
287x = 50,225
x = 175
Share of B in profit = 99x = 99 × 175
= 17,325
The ratio of volume of a cone to that of a cylinder if cylinder radius is 1/3 times and its height is 5 times to that of the cone, is
Let radius of the base and height of the cone be ‘r’ & ‘h’ respectively.
Then, volume of cone = πr2h / 3
For cylinder, radius = r/3
And, height = 5h
Volume of cylinder = πR2H = π (r/3)2 (5h) = π r2 5h/9
Ratio of volume of cone to volume of cylinder = (πr2h/3) : (5πr2 h/9)
Or, Ratio = 3 : 5
A man has a pass of two matches A and B which is going to be held at the same time. For match A man has 5 different level passes and for match B man has 4 different level passes. How many ways he can watch the match ?
Either he will attend match A or match B as both of them are held at the same time.
So number of ways = 5+4 = 9 ways
Directions For Questions
Direction: Answer the questions based on the information given below.
Pie chart below shows the percentage production of wheat by 5 different farmers and bar graph shows the percentage of sales by these farmers in 2010
Total production of wheat by 5 farmers = 2400 kg
...view full instructions
What is the ratio of total wheat sold by the farmers Q and T together to the total wheat produced by farmer Q and T together?
According to the data from the question, we get
Total wheat produced by farmer Q = 2400 × 28/100 = 672 kg
Total wheat sold by farmer Q = 672 × 75/100 = 504 kg
Total wheat produced by farmer T = 2400 × 17/100 = 408 kg
Total wheat sold by farmer T = 408 × 75/100 = 306 kg
Total wheat produced by the farmers Q and T together
= 672 + 408 = 1080 kg
Total wheat sold by the farmers Q and T together = 504 +306 = 810 kg
Required ratio = 810/1080 = 3 : 4
What is the average of wheat (in kgs) produced by all the farmers together?
Total Production = 2400 kg
Required average = 2400/5 = 480
If the production of wheat for farmer P increased by 10% in 2011 and sales also increased by 25% in 2011 from the previous year, then find the ratio of production of wheat for farmer P in 2011 to that of sales in the same year.
With the help of the data from the question, we get
Total wheat produced by farmer P in 2010= 2400 × 20/100 = 480 kg
Total wheat produced by farmer P in 2011= 480 × 110/100 = 528 kg
Total wheat sold by farmer P in 2010 = 480 × 90/100 = 432 kg
Total wheat sold by farmer P in 2011= 432 × 125/100 = 540 kg
Wheat’s sales is lowest for which of the farmer?
Wheat sold by the farmers Q and T together is how much percent more or less than the wheat produced by farmer P?
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