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Simple Interest Test 93
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Simple Interest Test 93

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  • Question 1/5
    1 / -0
    A Sum when invested at 12% simple interest amounts to Rs. 4810 in 4 years. Find the sum.
    Solutions
    Let the sum be Rs. x.
    S.I = Rs. = Rs.

    Amount = Rs.     = Rs.
      = Rs. 4810 => x = = Rs. 3250
  • Question 2/5
    1 / -0
    Kruti took a loan at simple interest rate of 6% in the first year with an Increase of 0.5% in each subsequent year. She paid Interest of ₹ 3375 after four years. How much loan did she take?
    Solutions
    Suppose the principle is ₹ x



    x = ₹12500
  • Question 3/5
    1 / -0
    A sum of money at simple interest amount to Rs. 300 in 4 years and Rs. 325 in 6 years. Find the rate of interest per annum.
    Solutions
    Interest for 2 years = 325 − 300 = Rs. 25
    Interest for 1 year = 25/2 = Rs. 12.5
    Interest for 4 years = Rs. 50
    Sum of money = 300 − 50 = Rs. 250
    Rate of interest = (12.5/250) × 100 = 5%
  • Question 4/5
    1 / -0
    Rs.6000 is lent out in two parts. One part is lent at 7% p.a. simple interest and the other is lent at 10% p.a. simple interest. The total interest at the end of one year was Rs.450. Find the ratio of the amounts lent at the lower rate and higher rate of interest.
    Solutions
    Let the amount lent at 7% = x
    Amount lent at 10% = 6000 – x
    Total interest for one year on the two sums left

    = 450
    x = 5000
    Amount lent at 10% = 1000
    Required ratio = 5000: 1000 = 5: 1
  • Question 5/5
    1 / -0
    Raj borrowed total Rs. 3,500 from two money lenders at simple interest. For one loan, he paid 5% p.a. and for the other, he paid 10% p.a. The total interest paid for two years was Rs.500. How much did he borrow at 10% rate?
    Solutions
    Let he borrowed Rs. X at 5% rate of interest. 
    Therefore, he borrowed at 10% = Rs. (3500 − X)
    According to question, 
    [X × 5 × 2)/100] + [(3500 − X) × 10 × 2)/100] = 500
    ⇒ X = Rs. 2000
    Hence sum borrowed at 10%rate
    = 3500 − 2000 = Rs. 1500
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