Total screw = 300

Number of possible outcomes = 300

Rusted screws = One fifteenth of 300

=

= 20

Number of remaining good screw = 300 – 20

= 280

Number of favorable outcomes = 280

Probability of getting good screw = P(E)

P(E) =

=

 The year 1995 is a non-leap year out of two friends say Raju’s birthday can be any day of 365 days in a non-leap year also Hamu’s birthday can be any day of 365 days of the same year so the total number of outcomes is = 365, we assume all those 365 outcomes are equally likely.

Let E be the event (Raju and Hemu have the same birthday)

Then the number of favorable outcomes to the event

n(E) = 1

P(E) =

=

 Total number of letters = 5

Number of vowels in the word TIGER = 2

P(E) =

P(E) =

 Number of 50 paise coin = 200

Number of 1₹ coin = 70

Number of 2₹ coin = 50

Number of 5₹ coin = 30

Total number of coins = 200 + 70 + 50 + 30

= 350

Probability that coin will not be ₹ 5 coin

P(E) =

=

=

=

 Here S = [HH, HT, TH, TT]

Let E = event of getting at least one tail = [HT, TH, TT]

Therefore P(E) =

=

Average production =

= 45 × 1000

= 45,000 tonnes.

Years which were more than the average = 2013, 2017, 2018.

Percentage increase =

=

= 250 %

Average production of 2018 and 2011 =

So, from the options it is clear that option A has the same average.

Percentage decrease =

=

= 75 %

Production in 2015 = 45 tonnes

Production in 2016 = 40 tonnes

Required ratio = 45 : 40 = 9 : 8