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INET Mixture & Alligation Test 207
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INET Mixture & Alligation Test 207

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  • Question 1/5
    1 / -0
    A solution of ‘THANDA SHARBAT’ has 15% sugar. Another solution has 5% sugar. How many liters’ of the second solution must be added to the 20L of first solution to make a solution of 10 % sugar :
    Solutions

    Let x L solution of 2nd mixture is added into 1st mixture to make the concentration of sugar 10 %.

    The quantity of sugar in 1st mixture = 15% of 20 L

    The quantity of sugar in 2nd mixture = 5% of a L

    And total quantity of solution = (20+a) L

    Now, according thee question

  • Question 2/5
    1 / -0
    48 litre of Glycerin is mixed with 144 litre Rose water. D litre of total mixture is taken out and 32 litre Glycerin and 48 litre Rose water are added in the mixture. The final mixture contains 30% Glycerin, find the quantity of the mixture that is taken out.
    Solutions

    Total mixture = 48+144 = 192 L

    % of glycerin= (48/192)x100% =25% and % of rose water = 75%

    In the final mixture, % of glycerin = 30% and % of rose water = 70%

    Ratio = 30:70 = 3:7

  • Question 3/5
    1 / -0
    Alloy A contain 70% copper and rest is tin. Alloy B contain 84% copper, 10% tin & rest are impurities. In which ratio both alloys are mixed so that in new mixture % of tin will be 20% ?
    Solutions

     Alloy A contain 30% tin while Alloy B contain 10% of tin

    So Alloy A Alloy B

    1 : 1

    So, both alloys should mixed in 1:1 so that in new mixture % of tin will be 20%

  • Question 4/5
    1 / -0
    A vessel contains a mixture of kerosene and petrol in the ratio of 2:5. When 3 liters of mixture oil are drawn off and replaced by same quantity of kerosene, the ratio of kerosene and petrol becomes 2:3. How many liters of liquid kerosene was there in the container?
    Solutions
    Suppose the container initially contains liters of kerosene and liters of petrol.
    After replacement, the kerosene left in mixture


    Petrol left in the mixture


    initially kerosine =2x=75/14
  • Question 5/5
    1 / -0
    In a city, the ratio of the number of men to number of women is 3:2. If number of men increases by 10% & number of women decreases by 500 then final population of city increases by 5%. Find initial number of men in city.
    Solutions
    Given number of men increases by 10% and Let number of women decreases by x%

    Ratio of number of men to number of women = 3:2 = 15:10

    ⇒ 5% - x% = 7.5%

    =>

    Negative sign shows that number of women is decreasing.

    According to question

    2.5% = 500

    1% = 200

    100% = 20000

    Hence total number of women = 20000

    Now, ratio of number of men to number of women is 3:2

    2 unit = 20000

    1 unit = 10000

    3 unit = 30000

    Hence initial number of men in city = 30000

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