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( × 2460) – ( × 1300) = ? + 67
492 – 143 = ? + 67
? = 349 – 67 = 282
÷ ? × (15.05)2 = 449.53
× 225 = 450
? = = 12
What is ratio of marks of Sumant in Hindi to marks of Abhinandan in science?
After adding marks of all students we get
Since Tarun got highest marks i.E. 455 out of 500
So highest percentage will be of Tarun
Solving percentage we get,
Sum of marks obtained by all students = 764 + 186 = 950
After solving , Calculating marks of all the students we get
Average percentage of Ankur= = 63.3 %
After calculating the marks total of all students we get,
Required Ratio is 86: (38+75)
=86:113
Hence required ratio =86:113
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