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RRB NTPC Aptitude Test - 95
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RRB NTPC Aptitude Test - 95

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  • Question 1/10
    1 / -0

    Find the time taken by train 180 mins long to cross a platform twice its length if it crosses a standing man in just 30 sec.

    Solutions

    To cross its length it takes 30 sec. To cross a platform twice its length, then it has to travel thrice its length. As distance and time are proportional if the speed remains constant then its time should increase three times i.e 3×30=90 sec.

     

  • Question 2/10
    1 / -0

    A certain amount earns an interest three times of itself in 6 years, at some rate of compound interest. In how many years would the amount become 256 times of itself?

    Solutions

    In 6 yrs,

    Amount = P +3P = 4P

    4P → 6 years

    256 → 44

    6 × 4 = 24 years

     

  • Question 3/10
    1 / -0

    A Sum of money becomes 2560 in 3 yrs and 5000 in 6 years at compound interest with annual compounding. What is the rate of interest?

    Solutions

    Now 2560 must have been multiplied by some factor thrice time to get 5000

    2560 (x) (x) (x) = 5000

    = X^3 =5000/2560

    X=5/4

    X= (1+ 1/4 )

    RATE = 25%

     

  • Question 4/10
    1 / -0

    The share of A is thrice that of C and twice that of B. If they invested for a year, and gained a profit of 55000. Then determine what will A get.

    Solutions

    Soln

    A=   2*B=    3*C = K , THEN

    A:B:C=6:3:2

    A+B+C=11

    A =6/11*55000=30,000

     

  • Question 5/10
    1 / -0

    The ratio of the shares of A and B and C are 9:13:7. Then divide the sum of RS 1740 among them.

    Solutions

    Soln

    A+b+C= 29

    1740/29=60

    HENCE OPTION 1 IS CORRECT

     

  • Question 6/10
    1 / -0

    IF in a triangle tan A =9/40 and sec A =41/40 then ,cosec A=?

    Solutions

     

  • Question 7/10
    1 / -0

    The angle of elevation of an aeroplane flying vertically above the ground,as observed  from the two consecutive stones 1km apart are 45 degrees  and 60 degrees . the height  of the aeroplane from the ground is.

    Solutions

    CONSEDERING TRIANGLE ABC

    BC= H/√3

    NOW IN TRIANGLE ABD

    BD = H

    BUT BD- BC = 1 KM

    ENCE   H - H/√3  = 1

    ON SOLVING WE WILL GET OPTION 4 AS ANS

     

  • Question 8/10
    1 / -0

    Solutions

    Soln

    Sin 60=   (√3)/(2 )

    Hence (a+b)/2 =60

    A+B =120

    AND C =60

    C/2 =30

    HENCE SIN 30=1/2 (OPTION 1)

     

  • Question 9/10
    1 / -0

    The  diagonal of a rectangle  is 12 cm and breadth 8cm. Find the Length of the rectangle is 

    Solutions

    Diagonal2 = length2 + breadth2

    122 = L2 + 82

    144 – 64 =L2

    Length = √80

    Length = √16*5

    Length = 4√5

     

  • Question 10/10
    1 / -0

    Find the volume of a prism with a square base of side 6 cm and height of 30 cm?

    Solutions

    Volume of prism = area of base * height

    = 6*6 *30=1080.

     

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