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Aptitude Test 113
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Aptitude Test 113

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  • Question 1/10
    1 / -0

    A train cover a distance of 660 m in 2 minutes and a bus cover a distance of 9 km in 45 min find the ratio of speed of train to bus?

    Solutions

    Distance of train = 660 m = 6600 mm

    Time taken by train = 2 mins

    Speed of train = 6600/2 = 330 m/min

    Distance of bus = 9 km =9000 m

    Time taken by bus = 45 mins

    Speed of the bus =9000/45 = 200 m/min

    Required ratio= 330/200 =33: 20

     

  • Question 2/10
    1 / -0

    Simplify: (-4.5) (3.5) ÷ (- 5 + 0.5) + 0.5

    Solutions

    (-4.5) (3.5) ÷ (- 5 + 0.5) + 0.5

    = (-15.75) ÷ (- 4.5) + 0.5

    = 3.5 + 0.5

    = 4

     

  • Question 3/10
    1 / -0

    If an item is sold at 450 profit percentage is same as loss percentage when it sold at 270.Find the selling price of that item if shopkeeper wants to earn 15% profit?

    Solutions

    450 – CP = CP – 270

    2CP = 720

    CP = 360

    Selling price at 15 % gain = 360 x 115/100 = Rs.414

     

  • Question 4/10
    1 / -0

    Find the number of trailing zero in the following series

    1 × 2 × 3 × 4 × 5 ……………….. 59 × 60

  • Question 5/10
    1 / -0

    Four bells ring at interval of 3, 4, 8 and 12 second respectively. In 24 min how many times they ring together?

    Solutions

    LCM of (3, 4, 8, 12) = 24

    After every 24 sec all bells ring together

    24 min = 24×60 sec

    So in 1440 sec they ring together = 1440/24 = 60 times

     

  • Question 6/10
    1 / -0

    Find the equivalent ration number of recurring decimal 0.25252525

  • Question 7/10
    1 / -0

    16 women can complete a work in 20 days .10 men and 10 women can complete the work in 8 days then in how many days 10 men alone can complete the work?

    Solutions

    One Woman can complete the work in 16 × 20 = 320 days

    10 women can complete the work in = 32 days

    10 men + 10 women = 1/8 days

    10 men + 1/32 = 1/8 days

    10 men = 1/8 – 1/32 = 3/32

    10 men can complete the work in 10 2/3 days

     

  • Question 8/10
    1 / -0

    Aarthi has 60 currency notes, which have the denomination of Rs. 10 and of Rs. 5. How much amount did she have in the denomination of Rs. 5 if the total value of the currency notes is Rs.500?

    Solutions

    Let number o f Rs. 5 note = x

    So number of 10 Rs note = 60 – x  

    ATQ, 5x + 10(60 – x) = 500

    5x + 600 – 10x = 500

    100 = 5x   → x = 20

    So amount she have in 20 denomination = 20 × 5 = 100

     

  • Question 9/10
    1 / -0

    The average weight of 7 student’s decrease by 1.5 kg when is out of class. What might be the weight of the student who is gone?

    Solutions

    Let be the old average is x kg

    (7x – age of student who is gone)/6   = x- 1.5

    7x – age of student who is gone = 6x - 9.0

    Age of student who is gone = x + 9

    We cannot determine the age without knowing X.

     

  • Question 10/10
    1 / -0

    At present price of a bike is Rs.48000 which is decreasing Rs.1300 per year and another bike of price 36000,which is increasing at Rs.1100 per year.In how many years will the price of these two bike be equal?

    Solutions

    Let the price be equal after t years

    48000 – 1300t = 36000 + 1100t

    2400t = 12000

    T = 5 year

     

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