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Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give answer as,
Quantity I: Rahul invests Rs.4500 in simple interest scheme for 4 years. After 4 years he received the total amount is Rs.7200, find the rate of interest?
Quantity II: Difference between the simple and compound interest on the sum of Rs.4000 for two years is Rs.90. Find the rate of interest?
From Quantity I,
SI = 7200 – 4500 = 2700
2700 = (4500 * 4 * R)/100
R = 15%
From Quantity II,
Difference = (P * R * R)/(100 * 100)
90 = (4000 * R * R)/(100 * 100)
Quantity I = Quantity II
Quantity I: Ratio of the ages of A to B is 2: 3 and after 12 years the ratio becomes 14: 19. What is A’s age after 5 years?
Quantity II: Ratio the ages of A to B is 6: 5 and the average of the ages of A and B after 4 years is 31.5 years. What is A’s present age?
(2x + 12)/(3x + 12) = 14/19
42x + 168 = 38x + 228
4x = 60
x = 15
A’s age = 2 * 15 = 30
A’s age after 5 years = 30 + 5 = 35 years
(6x + 4 + 5x + 4)/2 = 31.5
11x = 55
x = 5
A’s age = 6 * 5 = 30 years
Quantity I > Quantity II
Quantity I: A milkman has 45 liters mixture of milk and water in the ratio of 5: 4. If 10 liters water is added, then what is percentage of water in the final mixture?
Quantity II: A vessel contains 40 liters mixture of water and acid in the ratio of 3: 2. If 20 liters of mixture is taken out and replaced by water, then what percentage of acid in the final mixture?
Milk in 45 liters = 5/9 * 45 = 25 liters
Water in 45 liters = 4/9 * 45 = 20 liters
Required percentage = (20 + 10)/(45 + 10) * 100 = 54.54%
Water in 40 liters = 40 * 3/5 = 24 liters
Acid in 40 liters = 40 * 2/5 = 16 liters
Water in 20 liters = 20 * 3/5 = 12 liters
Acid in 20 liters = 20 * 2/5 = 8 liters
Final quantity of water = 24 – 12 + 20 = 32
Final quantity of acid = 16 – 8 = 8 liters
Required percentage = 8/(8 + 32) * 100 = 20%
Quantity I: A and B started a business with the investment of Rs.x and Rs.(x + 1000). At the end of one year the total profit is Rs.1700 and B’s profit share is Rs.1100, what is A’s initial investment?
Quantity II: Rs.1600
A’s share = 1700 – 1100 = 600
x/(x + 1000) = 600/1100
6x + 6000 = 11x
5x = 6000
x = 1200
Quantity I < Quantity II
Quantity I: If the cost price of the table is Rs.1800 and the shopkeeper offer a discount of 10% while he earned the profit of 15%. What is the marked price of the table?
Quantity II: If the ratio of the marked to cost price of the article is 5: 4 and the shopkeeper offers a discount of Rs.120 while he gets the profit of 20%.Find the cost price of the article?
CP = 2000
MP * 90/100 = 1800 * 115/100
MP = 2300
CP of article = 4x
MP of article = 5x
5x – 120 = 4x * 120/100
0.2x = 120
x = 600
CP = 600 * 4 = 2400
Average of the ages of A and B is 30 years and the average of the ages of A, B and C is 36 years. If the ratio of the ages of C to B is 2: 1, then what is the present age of A?
Sum of the ages of A and B = 30 * 2 = 60
Sum of the ages of A, B and C = 36 * 3 = 108
C’s age = 108 – 60 = 48 years
B’s age =1/2* 48 = 24 years
A’s age = 60 – 24 = 36 years
A and B started the business with the investment of Rs.2000 and Rs.2200 respectively. After 6 months B left and C joins with the investment of Rs.3200, at the end of 15 months the total profit is Rs.3000, then what is the profit share of B?
Profit ratio of A, B and C = (2000 * 15): (2200 * 6): (3200 * 9)
= 25: 11: 24
B’s profit share = 11/60 * 3000 = Rs.550
If the ratio of the cost price of table to chair is 5: 4 and the shopkeeper earns the profit of table and chair is 20% and 15% respectively. If the difference between the selling price of table and chair is Rs.280, then find the cost price of table?
SP of Table = 5x * 120/100 = 6x
SP of chair = 4x * 115/100 = 4.6x
6x – 4.6x = 280
1.4x = 280
x = 200
CP of table = 200 * 5 = 1000
If the ratio of the speed of car A to B is 5: 4 and the ratio of the speed of car B to C is 5: 3. If the time taken by car A to cover 120 km in 4.8 hours, then what is the speed of car C?
Speed of car A = 120/4.8 = 25 kmph
Speed of car B = 4/5 * 25 = 20 kmph
Speed of car C = 3/5 * 20 = 12 kmph
A alone completes the work in 30 days. If the efficiency of A is 20% more than B and B and C together can complete the work in 12 days. How many days C alone complete the work?
A = 30 days
Time ratio of A to B = 5: 6
B alone complete the work = 30 * 6/5 = 36 days
B + C = 1/12
C alone complete the work = 1/12 – 1/36 = 1/18
Correct (-)
Wrong (-)
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