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Aptitude Test 111
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Aptitude Test 111

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  • Question 1/10
    1 / -0

    12 women can complete a work in 15 days. 9 men can complete the same work in 14 days. Find the ratio of man to woman efficiency.

    Solutions

    12 women can complete work = 15 days

    1 woman can complete the work = 15 × 12 days

    1 woman 1 day work = 1/(15 × 12)

    9 men can complete work = 14 days

    1 man can complete the work = 14 × 9 days

    1 man 1 day work = 1/(14 × 9) days

    Ratio of efficiency = 1/(14 × 9) /1/(15 × 12) = (15 × 12)/(14 × 9) = 10 : 7

     

  • Question 2/10
    1 / -0

    Income of a person doubles after every year. If the initial income 3 lakhs per annum what will be the income at the start of 4th year?

    Solutions

    Income in 1 year = 3 lakh

    After 1st year = 3 × 2 = 6 lakh

    After 2nd year = 6 × 2 = 12 lakh

    After 3rd year = 12 × 2 = 24 Lakh

     

  • Question 3/10
    1 / -0

    If area of a square is 10.89 cm2 and area of Second Square is 13.69 cm2 then find the area of square whose side is equal to the sum of sides of both the square?

    Solutions

    Area of square1 = 10.89

    Side2 = 10.89 → Side1 = 3.3 cm

    Area of square2 = 13.69

    Side2 = 13.69 → Side2 = 3.7 cm

    Side of new square = 3.7 + 3.3 = 7 cm

    Area = 7 × 7 = 49 cm2

     

  • Question 4/10
    1 / -0

    If Sec A = 10/6 then what will be the value of Cot A?

    Solutions

    Sec A= Hypotenuse /Base =10/6

    Hypotenuse2 = Base2 + Length2

    100 – 36 = L2

    L =√64 = 8 cm

    Cot A = Base/Length = 6/8 = 3/4

     

  • Question 5/10
    1 / -0

    After a certain sum of chocolate increase in the chocolates box it becomes three times the half of its previous number of chocolates. Find the percentage of increase?

    Solutions

    Let number of chocolates = x

    New number of chocolate = 3x/2

    Required percentage of increase =

     

  • Question 6/10
    1 / -0

    Given that x and y are whole numbers and x y = 13. Find the value of x2 + y2? 

    Solutions

    x and y are whole numbers so x = 13 y = 1 or x = 1 and y = 13 is possible

    In either case x2+ y2 = 132 + 12 = 169 + 1 = 170

     

  • Question 7/10
    1 / -0

    If the compound interest on a certain sum for two years at 5% per annum is 20.50 then what is the SI for the same time at same rate of interest?

    Solutions

    Amount = P (1+ R/100)2

    P + 20.50 = P( 1 + 5/100)2

    P + 20.50 = 441P/400

    ((441 – 400) P)/400 = 20.50

    41P = 2050 × 4                  

    P = Rs. 200

    SI = (200 × 5 × 2)/100 = Rs.20

     

  • Question 8/10
    1 / -0

    Find one of the zeros of polynomial x2 – 22 x = 203

    Solutions

    x2 – 22 x – 203 = 0

    → x2 – 29 x + 7x – 203 = 0

    x (x – 29) + 7 ( x – 29) = 0

    (x – 29) (x + 7) = 0

    x = 29, - 7

     

  • Question 9/10
    1 / -0

    A ladder leaning against a wall make an angle of 300 with the ground if the length of ladder is 18 m find the distance of foot of the ladder from the wall?

    Solutions

     

    cos θ = BC/AC

    Cos 30 = BC/18

    √3/ 2 = BC/18

    BC = 9√3 cm

     

  • Question 10/10
    1 / -0

    If time taken by boat in upstream is three times that of taken by boat in downstream. A boat can cover48 km in 4 hour with the flow of stream. What is the speed of stream?

    Solutions

    Time taken by boat upstream (u) = 4 ×3 = 12 hr

    Downstream speed of boat (v) = 48/4 = 12 km/hr

    Upstream speed of boat = 48/12 = 4 km/hr

    Speed of stream = (u - v)/2 = (12 – 4)/2 = 8/2 = 4 km/hr

     

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